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zepelin [54]
3 years ago
15

DUE BY 3:30 For the following figure , the value of x is

Mathematics
1 answer:
IgorC [24]3 years ago
3 0

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

x = 8 \:  \: in

y = 8 \sqrt{2}  \:  \:  \: in

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

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The weight Wkg of a metal bar varies jointly
maria [59]

Answer:

d = \sqrt{\frac{216W}{35L} }

Step-by-step explanation:

Given that W varies jointly as L and d² then the equation relating them is

W = kLd² ← k is the constant of variation

To find k use the condition W = 140 when d = 4 and L = 54, thus

140 = k × 54 × 4² = 864k ( divide both sides by 864 )

\frac{140}{864} = k , that is

k = \frac{35}{216}

W = \frac{35}{216} Ld² ← equation of variation

Multiply both sides by 216

216W = 35Ld² ( divide both sides by 35L )

\frac{216W}{35L} = d² ( take the square root of both sides )

d = \sqrt{\frac{216W}{35L} }

6 0
3 years ago
a un baile asistieron 270 personas.si los boletos de costaban 100 pesos y los de dama 80 pesos y se recaudaron 24 800 pesos por
ser-zykov [4K]
The question in English
<span>A dance was attended by 270 people. If the gentlemen tickets cost 100 pesos and the lady tickets 80 pesos and 24800 pesos were collected for all the tickets. How many women and how many men attended the dance?

let
x---------> the number of men
y--------> the number of women

we know that
x+y=270----> x=270-y-----> equation 1
100x+80y=24800-------> equation 2
substitute equation 1 in equation 2
100*[270-y]+80y=24800----> 27000-100y+80y=24800
20y=2200-----> y=110
x=270-y----> x=270-110----> x=160

the answer is
the number of men ---> 160
the number of women----> 110

the answer in Spanish

</span>hagamos
x--------->la cantidad de hombres
y--------->la cantidad de mujeres

Sabemos que
x+y=270----> x=270-y-----> ecuacion 1
100x+80y=24800-------> ecuacion 2
sustituimos la ecuacion 1 en la ecuacion 2
100*[270-y]+80y=24800----> 27000-100y+80y=24800
20y=2200-----> y=110
x=270-y----> x=270-110----> x=160

La respuesta es
la cantidad de hombres es 160
la cantidad de mujeres es 110
4 0
3 years ago
What is the equation of a sine function with an amplitude of 2 and a period of 4pi.
Setler [38]

Answer:

um

Step-by-step explanation:

7 0
2 years ago
Can you please help me figure out 6m=<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B-1%7D%7B3%7D%20" id="TexFormula1" title=" \f
Rainbow [258]
-1/3 divided by six... m=-1/18
8 0
3 years ago
Read 2 more answers
PLEASE HELP ME WITH BOTH QUESTIONS<br> THANKS!!
vitfil [10]

First one:

cos(A)=AC/AB=3/4.24

cos(B)=BC/AB=3/4.24

Cos(A)/cos(B)=AC/AB / (BC/AB) = AC/AB * AB/BC = AC/BC=3/3=1


Second one:

To solve this problem, we have to ASSUME AFE is a straight line, i.e. angle EFB is 90 degrees. (this is not explicitly given).

If that's the case, AE is a transversal of parallel lines AB and DE.

And Angle A is congruent to angle E (alternate interior angles).

Therefore sin(A)=sin(E)=0.5

8 0
3 years ago
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