Simply solve for x:
-x^2 + 9 = 0 => x = 3 and x = -3;
plug x = 3 and x = -3 into the original equation you get 3 = 3 and -9 = -9, respectively;
So, the two intersecting points are (-3, -9), (3, 3).
And of course, the parabola opens down since its square term is minus.
I use indicators and line charts
There are total 80 dimes in the jar. B/c...
n+d=200 = n=200-d
0.05n+0.1d=$14.00
0.05(200-d)+0.1d=$14.00
10-0.05d+0.1d=$14.00
10+0.05d=$14.00
-10 -10
0.05d=$4.00
0.05d/0.05=$4.00/0.05
d=80
Let S be the set of whole numbers between 3 and 15 then <span>S={3,4,5,6,7,8,9,10,11,12,13,14,15}</span> so How many elements are in the set ? just count them..
Option B
Trevor isn't correct because -2i must also be a root
<em><u>Solution:</u></em>
For the polynomial with roots -7, 2i and 7 their roots can be,
1. ) Real roots
2.) Imaginary roots
The real roots are: -7 and +7
The imaginary root given is: 2i
The imaginary roots come from the square root. So they will be in form of
Therefore,
For f(x) with roots -7 and +7 and we have,
Fundamental Theorem of Algebra states that a polynomial will have exactly as many roots as its degree (the degree is the highest exponent of the polynomial).
So for f(x) with 4 roots, degree of f(x) is 4
So option B is correct. Trevor is not correct because –2i must also be a root.