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wariber [46]
3 years ago
9

Plzzzzz 100 points 3 questions plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

Mathematics
1 answer:
KonstantinChe [14]3 years ago
8 0

Answer:

do ur test by ur own understanding... xD

Step-by-step explanation:

<h3>all the natural numbers can be expressed in the form of the product of its prime factors.</h3>
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Does the parabola with equation x2 – x + 4 = 0 have real or imaginary roots?
Harman [31]
4. If the determinant delta of a quadratic equation is positive, the equation has two real roots. If the determinant is negative, it has two imaginary roots. In this case, delta=b^2-4ac=(-1)^2-4*1*4=-15. Therefore, this equation has two imaginary roots.
8 0
3 years ago
Read 2 more answers
If y = 3x and 2x + 4y = 12, then 2x + 4(3x) = 12
Kamila [148]

Answer:

x=6/7 and y=18/7

Step-by-step explanation:

If y = 3x and 2x + 4y = 12,

then substitute the value of y with 3x

2x + 4(3x) = 12

2x+12x=12

14x=12

x=12/14=6/7

y=3x=3*(6/7)=18/7

6 0
3 years ago
-10 + 5b = -35...I want to know the answer to this question pls...or else I will fail the 3rd quarter
Helen [10]

Answer:

-5

Step-by-step explanation:

-10+5b=-35

5b=-35-(-10)

5b=-35+10

5b=-25

b=-25/5

b=-5

7 0
3 years ago
Among a sample of 55 male soldiers the average shower time was found to be 2.95 minutes and the population standard deviation is
Oksanka [162]

Answer: -3.0593

Step-by-step explanation:

The test statistic for the difference between two population mean (when population standard deviations \sigma_1\ \&\ \sigma_2  are known ) is given by :-

z=\dfrac{\overline{x}_1-\overline{x}_2}{\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}}

where ,

n_1\ \&\ n_2 = Sample sizes taken from two  populations 1 and 2.

\overline{x}_1-\overline{x}_2 = Difference between two Sample mean.

\sigma_1\ \&\ \sigma_2 = Standard deviations of populations 1 and 2.

As per given , we have

n_1=55\ \&\ n_2=58

\overline{x}_1=2.95\ \&\ \overline{x}_2=3.3

\sigma_1=0.65\ \&\ \sigma_2=0.56

We assume that the data follows a normal distribution.

Then, the test statistic will be :-

z=\dfrac{2.95-3.3}{\sqrt{\dfrac{(0.65)^2}{55}+\dfrac{(0.56)^2}{58}}}\\\\=\dfrac{-0.35}{\sqrt{0.0130887}}\\\\=\dfrac{-0.35}{0.1144059}=3.05928278174\approx-3.0593  

Hence, the test statistic= -3.0593

5 0
3 years ago
Solve this A tourist starts off from town A and travels for 50km on a bearing of N80°W to town B.At town B ,he continues for ano
VLD [36.1K]

Answer:

The point C is 12.68 km away from the point A on a bearing of S23.23°W.

Step-by-step explanation:

Given that AB is 50 km and BC is 40 km as shown in the figure.

From the figure, the length of x-component of AC = |AB sin 80° - BC cos 20°|

=|50 sin 80° - 40 cos 20°|=11.65 km

The length of y-component of AC = |AB cos 80° - BC sin 20°|

=|50 cos 80° - 40 sin 20°|= 5 km

tan\theta= 5/11.65

\theta=23.23°

AC= \sqrt{5^2+11.65^2}=12.68 km

Hence, the point C is 12.68 km away from the point A on a bearing of S23.23°W.

8 0
3 years ago
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