Since we are given that the student has a brand Y phone, they are one of a sample of only 580 students. Since 80 of those students also own a brand X (they own both) the probability that the random student is one of those is 50/580 = 5/58 = 8.62%
Answer:
The probability that at least one internet user is more careful is 0.973
Step-by-step explanation:
We have been given that 70% of internet users are more careful about personal information when using a public wi-fi hotspot. Therefore, probability that a randomly chosen internet user is careful about the personal information would be 0.70.
We need to find the probability that among three randomly selected internet users, at least one is more careful. So, we can find the probability that none of the internet users is more careful and subtract that result from 1.
![1-C_{0}^{3}(0.70)^{0}(0.30)^{3-0}\\1-\frac{3!}{0!3!}(1)(0.30)^{3}\\1-(0.30)^{3}\\1-0.027\\0.973\\](https://tex.z-dn.net/?f=1-C_%7B0%7D%5E%7B3%7D%280.70%29%5E%7B0%7D%280.30%29%5E%7B3-0%7D%5C%5C1-%5Cfrac%7B3%21%7D%7B0%213%21%7D%281%29%280.30%29%5E%7B3%7D%5C%5C1-%280.30%29%5E%7B3%7D%5C%5C1-0.027%5C%5C0.973%5C%5C)
Therefore, the probability that at least one internet user is more careful is 0.973
<span> line passes through the points (p, a) and (p, –a)
where p and a are real numbers and p ≠ 0
(p, a) and (p, –a) m = Cannot divide by ZERO, there is no slope to this Line.
slope of the line: no slope (does not exist)
equation of the line: x = p Perpendicular Line
</span><span>slope of a line perpendicular to the given line: would be m = 0, horizontal Line y= 3
</span>y- intercept: none
240 miles/ 8 miles is not a rate if im not mistaken if im wrong someone correct me
Answer:
The exact amount of empty space is ![9\pi\ in^3](https://tex.z-dn.net/?f=9%5Cpi%5C%20in%5E3)
Step-by-step explanation:
we know that
To find out the exact amount of empty space, subtract the volume of the ball from the volume of the cylindrical can
step 1
Find the volume of teh ball
The volume of the sphere (ball) is given by
![V=\frac{4}{3}\pi r^{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E%7B3%7D)
we have
---> the radius is half the diameter
substitute
![V=\frac{4}{3}\pi (3)^{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20%283%29%5E%7B3%7D)
![V=36\pi\ in^3](https://tex.z-dn.net/?f=V%3D36%5Cpi%5C%20in%5E3)
step 2
Find the volume of the cylinder
The volume of the cylinder is given by
![V=\pi r^{2} h](https://tex.z-dn.net/?f=V%3D%5Cpi%20r%5E%7B2%7D%20h)
we have
---> the radius is half the diameter
![h=5\ in](https://tex.z-dn.net/?f=h%3D5%5C%20in)
substitute
![V=\pi (3)^{2} (5)](https://tex.z-dn.net/?f=V%3D%5Cpi%20%283%29%5E%7B2%7D%20%285%29)
![V=45\pi\ in^3](https://tex.z-dn.net/?f=V%3D45%5Cpi%5C%20in%5E3)
step 3
Subtract the volumes
![V=45\pi-36\pi=9\pi\ in^3](https://tex.z-dn.net/?f=V%3D45%5Cpi-36%5Cpi%3D9%5Cpi%5C%20in%5E3)