Commutative Property of Multiplication.
Hello from MrBillDoesMath!
Answer:
Top line: y = (2/3)x + 2
Bottom line: y = (2/3)x -1
Discussion:
The graph provided is hard to read but I did the best I could.
The top line appears to pass through the points (0,2) and (-3,0)
For this line
m = change y /change x = (0-2)/(-3-0) = -2/-3 = +2/3. So
y = mx + b => y = (2/3) x+ b. As the line passes through (0,2) set x = 0, y= 2 in y = (2/3)x + b =>
2 = (2/3) 0 + b => b = 2
Therefore y = (2/3)x + 2
The bottom line appears to pass through the points (0,-1) and (3,1)
For this line
m = change y /change x = (1-(-1)) /(3-0) = +2/-3. So
y = mx + b => y = (2/3) x+ b. As the line passes through (0,-1) set x = 0, y= -1 in y = (2/3)x + b =>
-1 = (2/3) 0 + b => b = -1
Therefore y = (2/3)x + -1
Thank you,
MrB
If 
, then by rationalizing the denominator we can rewrite
Now,
and
Answer:
It passes through the point (3,4). Given that the center of the circle is the point (0,0). We know that the equation of the circle is given by : (x-a)^2 + (y-b)^2 = r^2 where (a,b) is the center and r is the radius.
