Question

f^3+11g-4hf 3 +11g−4hf, cubed, plus, 11, g, minus, 4, h when f=3f=3f, equals, 3, g=2g=2g, equals, 2 and h=7h=7h, equals, 7.

Answer 1

Given:

The expression is:

$f^3+11g-4h$

The given values are $f=3,\ g=2,\ h=7$.

To find:

The value of the given expression for the given values.

Solution:

We have,

$f^3+11g-4h$

After substituting $f=3,\ g=2,\ h=7$, we get

$f^3+11g-4h=(3)^3+11(2)-4(7)$

$f^3+11g-4h=27+22-28$

$f^3+11g-4h=49-28$

$f^3+11g-4h=21$

Therefore, the value of the given expression is 21.