Answer: The answer is 35 degrees
34 times 50 plus 34 divided by 60 equals 28.9
Answer:
28(1 + 2t + w)
Step-by-step explanation:
This polynomial can be factored by factoring out 28.
28 + 56t + 28w = 28(1 + 2t + w)
A right triangle can only be formed when you use the 3/4/5 rule.
The 3/4/5 rule is a^2 + b^2 = c^2.
We will use 10 for a, 15 for b, and 20 for c.
a^2 + b^2 = c^2
Plug in 10 for a, 15 for b, and 20 for c.
10^2 + 15^2 = 20^2
10^2 = 100
15^2 = 225
20^2 = 400
100 + 225 = 400
This is not applicable, as 100 + 225 = 325.
Your answer is:
No, 10,15,20 does not form a right triangle.
I hope this helps!
Answer:
y = 3sin2t/2 - 3cos2t/4t + C/t
Step-by-step explanation:
The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt
Comparing the standard form with the given differential equation.
p(t) = 1/t and q(t) = 3cos(2t)
I = e^∫1/tdt
I = e^ln(t)
I = t
The general solution for first a first order DE is expressed as;
y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.
yt = ∫t(3cos2t)dt
yt = 3∫t(cos2t)dt ...... 1
Integrating ∫t(cos2t)dt using integration by part.
Let u = t, dv = cos2tdt
du/dt = 1; du = dt
v = ∫(cos2t)dt
v = sin2t/2
∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt
= tsin2t/2 - cos2t/4 ..... 2
Substituting equation 2 into 1
yt = 3(tsin2t/2 - cos2t/4) + C
Divide through by t
y = 3sin2t/2 - 3cos2t/4t + C/t
Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t
