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Leviafan [203]
3 years ago
10

Y = 5x - 10 Can you solve for x

Mathematics
2 answers:
laila [671]3 years ago
7 0
Use the slope-intercept form to find the slope and y-intercept.
Tap for more steps...
Slope:
5
5
y-intercept:
−
10
-
10
Any line can be graphed using two points. Select two
x
x
values, and plug them into the equation to find the corresponding
y
y
values.
tensa zangetsu [6.8K]3 years ago
6 0

Answer:

x = \frac{1}{5}y + 2     or       x = \frac{y+10}{5}     (Not sure which one is preferred in your case)

Step-by-step explanation:

<u>Key skills needed: Evaluating expressions</u>

1) We are given: y = 5x-10

2) To solve for the x variable, we want to leave the term with "x" by itself.

This means we add 10 to both sides

--> y + 10 = 5x (Since -10 and +10 cancel out to make 0 or nothing)

3) Then we divide by 5 on both sides to get "x" completely by itself.

-----> \frac{y+10}{5} = x

4) You can keep it as is so --> x = \frac{y + 10}{5}

or you can divide "y" by 5 and "10" by 5 and get --> x = \frac{1}{5} y + 2

(I am not sure which form is preferred one is preferred as the teacher matters)

<em>Hope you understood and have a nice day!!</em>

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(Please use a separate piece of paper to calculate the answer for this problem.) A study to determine the sensitivity and specif
mina [271]

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67.20\%

Step-by-step explanation:

Given

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3 years ago
The figure below is Circle E. Line CF is tangent at point C.
slava [35]

Answer:

Part 1) m

Part 2) m

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we know that

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therefore

m

Part 2) Find the measure of angle AKB

we know that

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3 years ago
Read 2 more answers
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bagirrra123 [75]

Answer:

C

Step-by-step explanation:

Asymptote is basically a line that the graph approaches but NEVER cuts/crosses.

<em><u>Remember, x = a where a is a constant is an equation of a vertical line and x = b, where b is a constant, is the equation of a horizontal line.</u></em>

<em><u /></em>

  • Looking at the graph, we can see that the curve doesn't cross an imaginary line at  x = 0, this is a vertical asymptote.
  • Also, we can see that the curve doesn't cross an imaginary line at y = -2, this is a horizontal asymptote.

Looking at the answer choices, the choice C is right.

3 0
4 years ago
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