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padilas [110]
3 years ago
15

GET THIS RIGHT GET BRAINLYEST!!! whats 4 plus 4?????

Mathematics
1 answer:
nirvana33 [79]3 years ago
8 0

Answer:

8

Step-by-step explanation:

4+4=8

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ziro4ka [17]
-infinity, positive infinity
8 0
3 years ago
How do i solve x-3/18 = 12/9? (Proportions and Ratios)
neonofarm [45]

Hey there!

\bold{x-\frac{3}{18}=\frac{12}{9}}

  • <em>Firstly, you have to simplify both sides of your equation </em>
  • \bold{x+\frac{-1}{6}=\frac{4}{3}}
  • <em>Secondly, you have to \bold{add} by  \bold{\frac{1}{6}} on each of your sides that you're working with </em>
  • \bold{x+\frac{-1}{6}+\frac{1}{6}=\frac{4}{3}+\frac{1}{6}}
  • \bold{Cancel:\frac{-1}{6}+\frac{1}{6}} because it gives you the result of  \bold{0}
  • \bold{Keep:\frac{4}{3}+\frac{1}{6}} because it gives you the answer for \bold{x}
  • \boxed{\boxed{\bold{Answer:x=\frac{3}{2}}}}

Good luck on your assignment and enjoy your day!

~\bold{LoveYourselfFirst:)}

5 0
3 years ago
What is the solution of the linear-quadratic system of equations?<br> y=x^2+5x-3<br> y-x=2
Nady [450]
-x=-y+2
x=y-2
now substitute iin the first one
y=(y-2)^2+5 (y-2)-3
y=y^2-4y+4 +5y-10-3
y=y^2+y-9
y^2-9=0.
y^2=9
y=3

3-x=2
-x=2-3
-x=-1
x=1

the solution are x=1 and y=3
3=1^2+5 (1)-3
3=1+5-3
3=6-3
3=3
4 0
4 years ago
Read 2 more answers
P and q are complex numbers such that ∣p∣ = 2/5 x + 2 , ∣q∣ = −3/4 x − 1 , and ∣p+q∣ = 2x + 4 .
Leya [2.2K]

Answer: (b)

Step-by-step explanation:

Given

\left |  p\right |=\dfrac{2}{5}x+2

\left |  q\right |=\dfrac{-3}{4}x-1

\left |  p+q\right |=2x+4

for two complex number, z_1,z_2

\left |  z_1+z_2\right |\leq \left |  z_1\right |+\left |  z_2\right |

Apply the above the property

\Rightarrow 2x+4\leq \dfrac{2}{5}x+2-\dfrac{3}{4}x-1\\\\\Rightarrow 2x+4\leq \dfrac{8x-15x}{20}+1\\\\\Rightarrow 2x+3\leq -\dfrac{7x}{20}\\\Rightarrow x\leq -\dfrac{60}{47}

Also, the absolute value of each complex number must be greater than or equal to zero

\text{Case-1}\\\\\Rightarrow \dfrac{2}{5}x+2\geq 0\\\\\Rightarrow x\geq -5\\\\\text{Case-2}\\\\\Rightarrow -\dfrac{3}{4}x-1\geq 0\\\\\Rightarrow x\leq -\dfrac{4}{3}\\\\\text{Case-3}\\\\\Rightarrow 2x+4\geq 0\\\Rightarrow x\geq -2

Taking the intersection of the above values of x, we get

x\in [-2,-\dfrac{4}{3}]  

8 0
3 years ago
Help❤️❤️❤️❤️❤️❤️❤️❤️
dexar [7]
Answer is Neither Will nor Olivia

hope it helps
7 0
3 years ago
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