Question

Alfonso leans a 20 ft ladder long against the wall with a base of 6 feet from the wall. How far up the wall does the ladder reach. Round to the nearest tenth if necessary

Answer 1

Answer:

19.1 ft

Step-by-step explanation:

-This a Pythagorean theorem problem given by the function:

$b^2+h^2=H^2$

Where

H is the Hypotenuse length

h is the perpendicular height

b is the base length.

#Given that H=20 ft and base length,b =6 ft, the perpendicular height is calculated as:

$h^2+b^2=H^2\\\\h^2=H^2-b^2\\\\h^2=20^2-6^2=364\\\\h=\sqrt{364}\\\\=19.0788\approx 19.08\ ft$$\approx 19.1 \ ft$

Hence, the ladder reaches the wall at a height of 19.1 ft