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Lorico [155]
3 years ago
9

Write an equation in slope-intercept form for the line that passes through (4, 1) and is parallel to the line y-1/4x+7

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
6 0

Answer:

y=¼x

Step-by-step explanation:

Parallel lines have the same slope

The slope of the given line is ¼,thus,

y-¼x+7=0

y=¼x-7

Now using the point-slope form y-y1=m(x-x1)

y-1=¼(x-4)

4y-4=x-4

4y=x-4+4

4y=x

y=¼x

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b = 2.77 m
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\displaystyle&#10;\frac{\sin A}{a} = \frac{\sin B}{b} \\ \\&#10;\sin A = \frac{a \sin B}{b} \\ \\&#10;A = \sin^{-1} \left[ \frac{a \sin B}{b}  \right] \\ \\&#10;A = \sin^{-1} \left[ \frac{4.33 \sin 25.9}{2.7708}  \right]  \\ \\&#10;A = 43.0467020

Find C with angles in triangle sum to 180

A + B + C = 180
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