Answer:
no solution
Step-by-step explanation:
12x − 18y = 27
4x − 6y = 10
Multiply the second equation by -3 so we can eliminate x
-3(4x − 6y) = 10*-3
-12x +18y = -30
Add the first equation to this new equation
12x − 18y = 27
-12x +18y = -30
------------------------
0 = -3
This is not a true equation, so there is no solution
What needs to be done first is to add up females and males that have passed.
42 + 14 = 56
so out of 56 students who passed 42 females passed 42/56 = 3/4 = 0.75
out of 56 students who passed, 14 males passed which turns into 14/56 = 1/4 = 0.25
check work; 0.75 + 0.25 = 1.00
NOW WE ARE DOING FAILS.
15 + 5 = 20
so out of 20 students who failed, 15 females failed so it turns into 15/20 = 3/4 = 0.75
out of 20 students who failed, 5 males failed. 5/20 = 1/4 = 0.25
check work; 0.75 + 0.25 = 1.00
i hope this helped! :)
V = 4/3 * pi * r^3
V = 4/3 * 3.14 * 21^3
Simplify exponent:
V = 4/3 * 3.14 * 9261
Multiply:
V = 38772.72
Answer: provided in the explanation segment
Step-by-step explanation:
(a). from the question, we can see that since that б is known, we can use standard normal, z.
we are asked to find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error?
⇒ 80% confidence interval for the average weight of Allen's hummingbirds is given thus;
x ± z * б / √m
which is
3.15 ± 1.28 * 0.32/√10
= 3.15 ± 0.1295 = 3.0205 or 3.2795
(b). normal distribution of weight (c) б is known
(c). option (a) and (e) are correct
(d). from the question, let sample size be given as S
this gives';
1.28 * 0.32/√S = 0.15
√S = (1.28 * 0.32) / 0.15 = 2.73
S = 7.4529
cheers i hope this helps
The answer is 6/5 (six over five) 100 divided by 20
