Answer:
The answer is below
Step-by-step explanation:
The formula m = (12,000 + 12,000rt)/12t gives Keri's monthly loan payment, where r is the annual interest rate and t is the length of the loan, in years. Keri decides that she can afford, at most, a $275 monthly car payment. Give an example of an interest rate greater than 0% and a loan length that would result in a car payment Keri could afford. Provide support for your answer.
Answer: Let us assume an annual interest rate (r) = 10% = 0.1. The maximum monthly payment (m) Keri can afford is $275. i.e. m ≤ $275. Using the monthly loan payment formula, we can calculate a loan length that would result in a car payment Keri could afford.

The loan must be at least for 5.72 years for an annual interest rate (r) of 10%
Answer:
<em>9</em>
Step-by-step explanation:
2(5y°) = 90° ⇒ y = <em>9</em>
So in long numbers or any number the positon determines its in the ones, tenths, hundredths
e.g
658
6 is in the hundredths as it is technically 600
5 is in the tenths as it is 50
8 is the ones as its just 8
Answer: x=−2
Step-by-step explanation:
x^3+2x^2+3x+6=0
(x+2)(x^2+3)=0
x+2=0 or x^2+3=0
x=−2
Answer:
14.286% savings
Step-by-step explanation:
299.99 / 349.99 = 0.8571..
1-0.8571= 14.286