3 3/5 & 18/5 are both equivalent
Step-by-step explanation:
3 3/5 = 18/5
<u>Write the mixed number as an improper fraction</u>
Step 1: Multiply the denominator by the whole number
5 × 3 = 15
Step 2: Add the answer from Step 1 to the numerator
15 + 3 = 18
Step 3: Write answer from Step 2 over the denominator
18/5
Therefore, 3 3/5 is equivalent to 18/5
Answer:
You are correct
Step-by-step explanation:
collinear means that they are on the same line, so they are collinear because of the definition of collinear
First recall that a microsecond is 10^−6 seconds. Hence, one second = 10^6 microseconds, one hour = 3600000000 = 3.6 • 10^9 microseconds, one month (assume a month has 30 days) = 2592000000000 = 2.592 • 10^12 microseconds, and one century = 3110400000000000 = 3.1104 • 10^15 microseconds.
Row 1: f(n) = log n In this case, we need to determine the largest n such that log n ≤ 1000000. To solve this inequality, we need to rewrite the inequality as 2^logn ≤ 2^1000000 or n ≤ 2^1000000. Recall from lecture that 2^10 ≈ 10^3, thus we have that 2^1000000 = 2^10•100000 = (2^10)^100000 ≈ (10^3)^100000 = 10^300000. This is the result given in the textbook. For one hour, we have that n ≤ 2^3600•1000000 and thus n ≈ 10^1080000000.
Row 8: f(n) = n! For us to see that the largest sized input is 12 that can be processed within an hour when f(n) = n! one can simply, compute 12! And verify that it is less than the number of microseconds in one hour, but that 13! is greater than the number of microseconds in an hour.
Row 4: f(n) = n log n In this case, use Maple to solve equations like n log n−1000000 = 0. The Maple command for solving this equation is fsolve(n*log[2](n) - 1000000 = 0)
Answer:
slope of p=-7/12
slope of q=-3/6.8
slope of r=-16/6.4
slope of m=6.2/15.5
slope of n=6.8/17
not yet simplified if it can be simplified
The answer would be 85% because 17/20= .85 and if you multiply that by 100 it’s 85
