Use Python.
1 answer:
Answer:
Explanation:
The code in the question is written in Java but If you want it in Python then it would be much simpler. The code below is writen in Python and uses list slicing to reverse the array that is passed as an argument to the function. The test case from the question was used and the output can be seen in the attached image below.
def reverse(arr):
reversed_arr = arr[::-1]
return reversed_arr
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Answer:
Check the explanation
Explanation:
#include <stdio.h>
#include <sys/stat.h>
#include <stdlib.h>
#include <fcntl.h>
#include <errno.h>
#include <unistd.h>
extern int errno;
struct stat st;
int main(int argc, char **argv){
int num1 = atoi(argv[1]); // Getting num1 from user
int num2 = atoi(argv[2]); // Getting num2 from user
char *fileSource = argv[3];
char *fileTarget = argv[4];
int source_fd = open(fileSource, O_RDONLY); // opening the file in read only mode
int target_fd = open(fileTarget, O_WRONLY | O_CREAT); // opening the target file in Writeonly mode if file is not found it will create
char *ch = (char *) calloc(num2+num1, sizeof(char));
stat(fileSource, &st);
if(st.st_size < (num1 + num2)){
printf("File Size is smaller than the specified bytes\n");
read(source_fd, ch, st.st_size); // reading the file upto the end
write(target_fd, ch, st.st_size); // write to the file
write(target_fd, ch, st.st_size); // two times writing to the file
}else{
if(lseek(source_fd, (off_t)num1, SEEK_SET) < 0 ) // moving the cursor to after the specified bytes from the start
{
printf("Some Error occured while seeking the file");
return -1;
}
read(source_fd, ch, num2); // reading num2 bytes from the source
write(target_fd, ch, num2); // writing two times to the target
write(target_fd, ch, num2);
}
return 0;
}
1 2 #include <stdio.h> #include <sys/stat.h> #include <stdlib.h> #include <fcntl.h> #include <errno.h> #include <unistd.h> 4
The code screenshot and code output are attached below.
