All categories

2 years ago

If x varies inversely with y², and x=10 when y=7. find x when y=10

Mathematics

2 answers:

yulyashka [42]2 years ago

7 0

Answer:

Step-by-step explanation:

Given

x varies inversely with y², then the function is:

x = k/y²

x = 10, y = 7, find the value of k by substituting the values of x and y:

10 = k/7²
10 = k/49
k = 10*49
k = 490

The function is:

x = 490/y²

When y = 10, the value of x is:

x = 490/10² = 490/100 = 4.9

astraxan [27]2 years ago

6 0

Answer:

Statement says that,

x varies inversely with y²

According to the above problem,we get

x=k/y², where k is a constant

Now, x=10 when y=7, so the value of k is

10=k/7²

k=10×7²

k=10×49

k=490

Hence, when y=10,

we have to find the value of x

So by putting the value of k, we get

x=490/(10)²

x=490/100

x=4.9

★ x=4.9 is the right answer.

You might be interested in

Can someone please help?

Shalnov [3]

Answer:

c. 50

Step-by-step explanation:

count each full block and every block that is more than half full as 1 each, ignore every block that is less than half full.

I got exactly 50 using this method before looking at the available answers.

In multiple choice math problems try to ignore the possible answers until you have determined what you think it ought to be. If the answer you found is in the list you have more confidence you are right, if the answer you got is not in the list you know you did something wrong... just a hint :)

4 0

2 years ago

Obtain the general solution to the equation. (x^2+10) + xy = 4x=0 The general solution is y(x) = ignoring lost solutions, if any

alukav5142 [94]

Answer:

$y(x)=4+\frac{C}{\sqrt{x^2+10}}$

Step-by-step explanation:

We are given that a differential equation

$(x^2+10)y'+xy-4x=0$

We have to find the general solution of given differential equation

$y'+\frac{x}{x^2+10}y-\frac{4x}{x^2+10}=0$

$y'+\frac{x}{x^2+10}y=4\frac{x}{x^2+10}$

Compare with

$y'+P(x) y=Q(x)$

We get

$P(x)=\frac{x}{x^2+10}$

$Q(x)=\frac{4x}{x^2+10}$

I.F= $e^{\int\frac{x}{x^2+10} dx}=e^{\frac{1}{2}ln(x^2+10)}$

$e^{ln\sqrt(x^2+10)}=\sqrt{x^2+10}$

$y\cdot \sqrt{x^2+10}=\int \frac{4x}{x^2+10}\times \sqrt{x^2+10} dx+C$

$y\cdot \sqrt{x^2+10}=\int \frac{4x}{\sqrt{x^2+10}}+C$

$y\cdot \sqrt{x^2+10}=4\sqrt{x^2+10}+C$

$y(x)=4+\frac{C}{\sqrt{x^2+10}}$

6 0

2 years ago

Angie can peel

Mekhanik [1.2K]

The answer is b plz mark me brainliest

5 0

3 years ago

Read 2 more answers

What is the solution to this system of linear equations?

nataly862011 [7]

Step-by-step explanation:

the question answer a should be

3 0

2 years ago

acme lumber purchased 13.145 pine wood and 16.903 cedar wood to sell in the store. after 6 months they had sold7.589 pounds of l

11111nata11111 [884]

Answer:

22.459 pounds of wood

Step-by-step explanation:

Total amount of wood in store = amount of pine wood purchased + amount of cedar in the store

Total amount of wood in store = 13.145 pine wood + 16.903 cedar wood

Total amount of wood in store = 30.048 pounds of wood

If acme lumber had sold 7.589 pounds of lumber after 6 months, the amount of pounds of woods that the company have left to sell = Total amount in store initially - amount sold after 6 months

Amount of pounds of woods that the company have left to sell = 30.048 - 7.589

The amount of pounds of woods that the company have left to sell = 22.459 pounds of wood

4 0

2 years ago