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S_A_V [24]
3 years ago
12

The members of the city cultural center have decided to put on a play once a night for a week. Their auditorium holds people. By

selling​ tickets, the members would like to raise ​$ every night to cover all expenses. Let d represent the number of adult tickets sold at ​$. Let s represent the number of student tickets sold at ​$ each. If all seats are filled for a​ performance, how many of each type of ticket must have been sold for the members to raise exactly ​$​? At one performance there were times as many student tickets sold as adult tickets. If there were tickets sold at that​ performance, how much below the goal of ​$ did ticket sales​ fall?
Mathematics
1 answer:
nika2105 [10]3 years ago
7 0

Answer:

a) At $3,300 for 600 seats, the average price per seat is 3300/600 = $5.50. The mix of tickets that results in that average can be found using an X diagram as shown below. The numbers on the right are the differences along the diagonals. When they are multiplied by 2, they add to 600. This shows that the required sales for revenue of $3,300 are

 200 adult tickets

 400 student tickets

b) When 3 student tickets are sold for each adult ticket, the average seat price is

 (3*$4.50 +7.50)/4 = $5.25

Then the shortfall in revenue is ...

 $3,300 -480*$5.25 = $780

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