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2 years ago

Jaxon is creating a mosaic design on a rectangular

Mathematics

2 answers:

Lina20 [59]2 years ago

6 0

Here are the answers

olasank [31]2 years ago

3 0

Answer:

hard question

Step-by-step explanation:

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the dot plot above identifies the number of pets living with each of 20 families in an apartment building .what fraction of fami

harkovskaia [24]

Answer:

B. ⅕

Step-by-step explanation:

Fraction of families having more than 2 pets = families with pets of 3 and above ÷ total number of families in the apartment

From the dot plot above, 3 families have 3 pets, and 1 family has 4 pets.

Number of families with more than 2 pets = 3 + 1 = 4

Fraction of families with more than 3 pets = $\frac{4}{20} = \frac{1}{5}$

4 0

2 years ago

A circle has a diameter of 36 cm. Which expression could represent the area of this circle in square cm?

goldenfox [79]

Answer:

Step-by-step explanation:

You haven't given the choices but I believe the equation below could represent the area of the circle:

(pi ~ 3.14) * (18)^2

The area for a circle is pi * radius squared, so to find the radius divide the diameter by 2.

8 0

2 years ago

Read 2 more answers

The figure shows the dimensions of the side panel of a skateboard ramp.

Helen [10]

Answer:

$A=28.7\ ft^{2}$

Step-by-step explanation:

we know that

The formula to calculate the area of a triangle applying the law of sines is equal to

$A=\frac{1}{2}(a)(b)sin(C)$

we have

$a=14\ ft$

$b=12\ ft$

$C=20\°$

substitute in the formula

$A=\frac{1}{2}(14)(12)sin(20\°)$

$A=28.7\ ft^{2}$

7 0

2 years ago

a) Use the triangle below to work out the exact value of sin 45°. 12 1 1 b) Hence, or otherwise, give the exact value of sin 135

MariettaO [177]

Answer:

258

Step-by-step explanation:

cause 1and 1 are the same size

3 0

1 year ago

Use induction to prove: For every integer n > 1, the number n5 - n is a multiple of 5.

nignag [31]

Answer:

we need to prove : for every integer n>1, the number $n^{5}-n$ is a multiple of 5.

1) check divisibility for n=1, $f(1)=(1)^{5}-1=0$ (divisible)

2) Assume that $f(k)$ is divisible by 5, $f(k)=(k)^{5}-k$

3) Induction,

$f(k+1)=(k+1)^{5}-(k+1)$

$=(k^{5}+5k^{4}+10k^{3}+10k^{2}+5k+1)-k-1$

$=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k$

Now, $f(k+1)-f(k)$

$f(k+1)-f(k)=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k-(k^{5}-k)$

$f(k+1)-f(k)=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k-k^{5}+k$

$f(k+1)-f(k)=5k^{4}+10k^{3}+10k^{2}+5k$

Take out the common factor,

$f(k+1)-f(k)=5(k^{4}+2k^{3}+2k^{2}+k)$ (divisible by 5)

add both the sides by f(k)

$f(k+1)=f(k)+5(k^{4}+2k^{3}+2k^{2}+k)$

We have proved that difference between $f(k+1)$ and $f(k)$ is divisible by 5.

so, our assumption in step 2 is correct.

Since $f(k)$ is divisible by 5, then $f(k+1)$ must be divisible by 5 since we are taking the sum of 2 terms that are divisible by 5.

Therefore, for every integer n>1, the number $n^{5}-n$ is a multiple of 5.

3 0

2 years ago