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sveticcg [70]
3 years ago
9

Find the key features for m [x]=3x^2+13x-30

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
8 0

Answer:

x1= -6 and x2= 5/3

Step-by-step explanation:

good luck

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2. Help ASAP!!!!!!!!!!!!!!!!
ch4aika [34]

ANSWER

2 \times 2

EXPLANATION

The dimensions of a matrix is of the form:

Row \times  Column

The dimensions of the first matrix is

2 \times 3

The dimensions of the second matrix is

3 \times 2

Since the inner products are the same,the outer products give the dimensions of the product of the two matrices.

(2 \times 3)(3 \times 2) = 2 \times 2

Therefore the dimensions of the product is a 2×2 matrix.

8 0
2 years ago
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What is the value of x in the equation 2x - 3 = 9- 4x? o 6 o 3 O 1 02​
riadik2000 [5.3K]

Answer:

2? The last one

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
-2+9=-2(x+3)+8<br> Is this Infinitely Many Solutions<br> No solutions<br> Or One solutions
Margarita [4]

Answer:

i think it is many but i am not sure

Step-by-step explanation:

3 0
3 years ago
What is the probability of drawing two yellow marbles if the first one is NOT placed back into the bag before the second draw?
polet [3.4K]

Answer:

2/10 on the first draw and 1/9 on the second draw

Step-by-step explanation:

In the first draw, 2 marbles are yellow out of 10, but on the second draw, you don't replace a yellow marble leaving 1 yellow marble out of 9 total marbles in the bag.

6 0
2 years ago
XYZ has coordinates X(2, 3), Y(1,4), and Z(8,9). A translation maps X to X'(4,7). What are the coordinates for Y' and Z' for thi
Rashid [163]

Answer:

The coordinates are Y'(x,y) = (3, 8) and Z'(x,y) = (10, 13).

Step-by-step explanation:

First, we have to derive an expression for translation under the assumption that each point of XYZ experiments the same translation. Vectorially speaking, translation from X to X' is defined by:

X'(x,y) = X(x,y) + T(x,y) (1)

Where T(x,y) is the vector translation.

If we know that X(x,y) = (2,3) and X'(x,y) = (4,7), then the vector translation is:

T(x,y) = X'(x,y)-X(x,y)

T(x,y) = (4,7) - (2,3)

T(x,y) = (2, 4)

Then, we determine the coordinates for Y' and Z':

Y'(x,y) = Y(x,y) + T(x,y)

Y'(x,y) = (1,4) + (2,4)

Y'(x,y) = (3, 8)

Z'(x,y) = Z(x,y) + T(x,y)

Z'(x,y) =(8,9) + (2,4)

Z'(x,y) = (10, 13)

The coordinates are Y'(x,y) = (3, 8) and Z'(x,y) = (10, 13).

7 0
2 years ago
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