Answer:
4√13
Step-by-step explanation:
1. Calculate the length of SN
Your triangle (below) is a relatively tall isosceles triangle.
∆STN is a right triangle, so we can use Pythagoras theorem to calculate the length of SN.
SN² + NT² = ST²
SN² + 4² =22²
SN² + 16 = 484
SN² = 468
SN = √468 = 6√13
2. Calculate the length of SX
UM and SN are lines from an angle to the centre of the opposite side, so they are medians.
The medians of a triangle meet at a single point, X — the centroid.
Another characteristic is that the centroid divides each median into segments in a 2:1 ratio.
Thus,
SX = ⅔SN = ⅔ × 6√13 = 4√13
Since AC = BC, we can say that this triangle is isoceles (at C)
In an isoceles triangle, the two angles that does not belong to the top angle (which in this case is C) is equal to each other.
Now, we can find the sum of the 2 missing angles : 180 - 52 = 128.
And since they are equal, we can find b : 128 : 2 = 64/
now, bear in mind, that zeroing out the denominator, also gives critical points, usually asymptotic points, where the derivative is undefined, now, in this case, the denominator is never zero, so we don't get any from the denominator, just from the numerator, and are 0 and 1
now check the picture below
running a first-derivative test on it, those are the values on those regions
you get a negative, regardless of what it might be, what matters is the sign
you get a positive, and then a negative
so, f(x) goes down, then up then down
now, you can see, there's on relative minimum and a relative maximum
Answer:
x=1.7099
Step-by-step explanation:
2x³=10
x³=10/2
x³=5
x=∛5
x=1.7099
Answer:
8 is your answer
Step-by-step explanation:
First plug in 6
6÷3+6
Then divide 6/3 which is 2
so 2+6 is 8
