Answer: $6,000
Step-by-step explanation: If set up correctly, the value of the car at the end of 2006 times 0.6 (because the car is losing 0.4 of its value, so it keeps 0.6 of its value) should get you the value of the car at the end of 2007.
The equation should look like this:
(value of the car at the end of 2006) x 0.6 = (value of the car at the end of 2007)
Then you substitute: (value at the end of 2006) x 0.6 = 3600
Then divide: (value at the end of 2006) = 0.6 ÷ 3600
Then substitute again: (value at the end of 2006) = 6,000
Hope this helped you! Feel free to ask me any questions!
< 1 and < 2......adjacent angles...because they have a common side and a comon vertex
< 1 and < 2.....complimentary angles....because when added, they equal 90
You take ten percent of 33, which is 3.3, and subtract it from the original price.
33-3.3=29.7 which means the final price is $29.70
<span>42:6=7, the dividend is 42, the quotient is 7
so 42= 6x7
8:1=8, 8=8x1
12= 1x12
generalization
let be a:b=q, so a = bx q, a dividend, q quotient and b the divisor</span>
Answer:
y=1/2x-1
Step-by-step explanation:
