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riadik2000 [5.3K]
3 years ago
15

Factorise 12u-uv please help lol

Mathematics
1 answer:
max2010maxim [7]3 years ago
6 0

Answer:

u(12-v)

Step-by-step explanation:

12u and -uv both have a factor of <em>u </em>in common, so we can pull it out to give us the factored expression u(12-v).

<em>Note on factoring:</em>

<em>Remember, it's just using the distributive property in reverse! We can get our original expression back by distributing the u to the 12 and the -v.</em>

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3 0
2 years ago
2% of the ducks in a pond have a fluffy tail. If 4 ducks have a fluffy tail, how many ducks are in the pond. Please answer best
GuDViN [60]

Answer:

200 ducks total in the pond

Step-by-step explanation:

2% of x equals 4

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6 0
3 years ago
On the farm, rather than use money, they exchange animals. The exchanges are as follows: 4 bunnies = 3 chickens, 5 chickens = 2
Radda [10]

We have to trade 5 bunnies for a donkey.

Solution:

To calculate how many bunnies could be exchanged for a donkey, we have to multiply the exchange rates of each animal/bird.

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One chicken = 2/5 pigs (0.4 pigs)

One pig = 2/3 donkeys (0.67 donkeys).

On multiplying all of the above rates we get,

0.75*0.4*0.67=0.2

Since we now know a bunnies worth is 0.2 donkey

Therefore, (1/0.2=5) 5 bunnies to trade for a donkey.

4 0
3 years ago
-5+13=k<br><img src="https://tex.z-dn.net/?f=%20-%205%20%2B%2013%20%3D%20k" id="TexFormula1" title=" - 5 + 13 = k" alt=" - 5 + 1
Vikentia [17]
Use the communicative property of addition to switch to order and you get
13 - 5, so the answer is 8, or k = 8

OR

-5 + 13 = k
Combine like terms
8 = k
or
k = 8<span />
5 0
3 years ago
Find an equation of the plane through the point (−1,−5,−2)(−1,−5,−2) with normal vector n=⟨−5,−4,−1⟩n=⟨−5,−4,−1⟩.
Ostrovityanka [42]
Consider this option:
1. given: n(A;B;C)=n(-5;-4;-1) and A(-1;-5;-2)=A(x₀;y₀;z₀).
Common view of equation for a plane is Ax+By+Cz+D=0, where A,B,C,D - numbers.
2. from another side using coordinates of A and normal vector it is possible to make up the equation: A(x-x₀)+B(y-y₀)+C(z-z₀)=0 ⇒ -5(x+1)-4(y+5)-(z+2)=0; ⇒ -5x-4y-z-27=0 or 5x+4y+z+27=0.
7 0
3 years ago
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