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3 years ago

Please help me~

Mathematics

2 answers:

grandymaker [24]3 years ago

4 0

Answer:

I think it’s B because if u notice the other two shapes are different sizes from eachother it’s barely noticable but it’s there

Step-by-step explanation:

maw [93]3 years ago

3 0

B, D and E are congruent of the pairs

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A 31 foot board is cut in two pieces so that the longer piece is 1 foot less than three times the shorter piece

strojnjashka [21]

X is the short piece
(3•x-1)+x=31
4x=31+1
X=32/4=8

Short piece is 8
Long piece is 3•8-1=23

Check 8+23=31 ✔️

8 0

3 years ago

Here's a graph of a linear function. Write the equation that describes that function. 8 Express it in slope intercept form. Ente

Stolb23 [73]

Answer:

f(x) = $\frac{1}{2}x+4$

Step-by-step explanation:

Let the equation of the function is,

f(x) = mx + b

Here, m = slope of the line

b = y-intercept

From the graph attached,

y-intercept 'b' = 4

Slope = $\frac{\text{Rise}}{\text{Run}}$

= $\frac{4}{8}$

= $\frac{1}{2}$

Therefore, equation of the function representing the graph will be,

f(x) = $\frac{1}{2}x+4$

5 0

3 years ago

Find the volume of the solid formed by revolving the region bounded by LaTeX: y = \sqrt{x} y = x and the lines LaTeX: y = 1 y =

Strike441 [17]

Answer:

The volume is:

$\displaystyle\frac{37\pi}{10}$

Step-by-step explanation:

See the sketch of the region in the attached graph.

We set the integral using washer method:

$\displaystyle\int_a^b\pi r^2dx$

Notice here the radius of the washer is the difference of the given curves:

$x-\sqrt{x}$

So the integral becomes:

$\displaystyle\int_1^4\pi(x-\sqrt{x})^2dx$

We solve it:

Factor $\pi$ out and distribute the exponent (you can use FOIL):

$\displaystyle\pi\int_1^4x^2-2x\sqrt{x}+x\,dx$

Notice: $x\sqrt{x}=x\cdot x^{1/2}=x^{3/2}$

So the integral becomes:

$\displaystyle\pi\int_1^4x^2-2x^{3/2}+x\,dx$

Then using the basic rule to evaluate the integral:

$\displaystyle\pi\left[\frac{x^3}{3}-\frac{2x^{5/2}}{5/2}+\frac{x^2}{2}\right|_1^4$

Simplifying a bit:

$\displaystyle\pi\left[\frac{x^3}{3}-\frac{4x^{5/2}}{5}+\frac{x^2}{2}\right|_1^4$

Then plugging the limits of the integral:

$\displaystyle\pi\left[\frac{4^3}{3}-\frac{4(4)^{5/2}}{5}+\frac{4^2}{2}-\left(\frac{1}{3}-\frac{4}{5}+\frac{1}{2}\right)\right]$

Taking the root (rational exponents):

$\displaystyle\pi\left[\frac{4^3}{3}-\frac{4(2)^{5}}{5}+\frac{4^2}{2}-\left(\frac{1}{3}-\frac{4}{5}+\frac{1}{2}\right)\right]$

Then doing those arithmetic computations we get:

$\displaystyle\frac{37\pi}{10}$

6 0

3 years ago

Help me plzzzzzzzzzzz

sammy [17]

I think the answer is 5

7 0

3 years ago

In discus competition an athlete threw the discus 63.37meters 62.95 meters and 63.7meters order the distance from least to great

Eduardwww [97]

62.95meters, 63.37meters, 63.7meters.

6 0

3 years ago

Read 2 more answers