(2x100)x9, is one possible way.
I don’t know man I’m sorry
Answer:
Female
Step-by-step explanation:
...look at those numbers dude
Answer:
1 quarter, 1 dime, and 4 nickels
Step-by-step explanation:
First you subtract the 18 cents that were found in the pocket from the total amount of 73 cents to get the total amount of the 6 other coins:
73-18=55.
So the total amount of the 6 coins equals 55 cents.
The quarter = 25 cents
The dime = 10 cents
The 4 nickels = 5 + 5 + 5 + 5 = 20
1 quarter, 1 dime, and 4 nickels add up to the necessary total of 6 coins and when you add up the total cents of the quarter, dime, and nickels, 25 + 10 + 20 it comes to the sum of 55, which is how much the 6 coins are worth in total.
So therefore, the answer is 1 quarter, 1 dime, and 4 nickels.
Answer:
P(C4) = 0.0711
Step-by-step explanation:
consider the first draw = 15/23 since it cannot be a blue ball
The second draw = 21/29 since 6 more red balls will be added after the draw since a blue ball cannot be drawn
the third draw = 27/35 since 6 more red balls will be added after each draw since a blue ball cannot be drawn
therefore the total number of red balls will be = 15 + 6 + 6 + 6 = 33 red balls after the 4th draw. the total ball now in the urn= 33 red + 4 blue = 41
Hence the probability of drawing a blue ball at the fourth draw after drawing red balls at the previous attempts = 8/41
P(C4) = P ( fourth ball is blue ) * P( first ball red)*P(second ball red) *P(third ball red )
= (8/41) * (15/23) * (21/29)* (27/35) = 0.0711