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Vedmedyk [2.9K]
1 year ago
15

agent bourne transferred classified files from the cia mainframe into his flash drive. the drive has 72 megabytes on it before t

he transfer, and the transfer happened at a constant rate. after 136 seconds there were 1,160 megabytes on the drive. the drive had a maximum capacity of 3,000 megabytes.
Mathematics
1 answer:
Eduardwww [97]1 year ago
4 0

Answer: The speed was 4.1 MB/sec.

We first find the amount that was transferred within the first 125 seconds:

549-36.5=512.5

Now we divide this by 125, the number of seconds:

512.5/125 = 4.1

The speed of the transfer is 4.1 megabytes per second.

It took 235 seconds for the drive to be completely filled.

Step-by-step explanation:

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Akio found 18 cents in his pocket. He found 6 more coins in his pocket. Altogether he has 73 cents. What were the 6 coins he fou
Dafna1 [17]

Answer:

1 quarter, 1 dime, and 4 nickels

Step-by-step explanation:

First you subtract the 18 cents that were found in the pocket from the total amount of 73 cents to get the total amount of the 6 other coins:

73-18=55.

So the total amount of the 6 coins equals 55 cents.

The quarter = 25 cents

The dime = 10 cents

The 4 nickels =  5 + 5 + 5 + 5 = 20

1 quarter, 1 dime, and 4 nickels add up to the necessary total of 6 coins and when you add up the total cents of the quarter, dime, and nickels, 25 + 10 + 20 it comes to the sum of 55, which is how much the 6 coins are worth in total.

So therefore, the answer is 1 quarter, 1 dime, and 4 nickels.

8 0
3 years ago
6. An urn contains 15 red balls and 8 blue balls. In each draw, one ball is extracted at random. It is then returned to the urn,
Leviafan [203]

Answer:

P(C4) = 0.0711

Step-by-step explanation:

consider the first draw = 15/23  since it cannot be a blue ball

The second draw = 21/29 since 6 more red balls will be added after the draw since a blue ball cannot be drawn

the third draw = 27/35 since 6 more red balls will be added after each draw since a blue ball cannot be drawn

therefore the total number of red balls will be = 15 + 6 + 6 + 6 = 33 red balls after the 4th draw. the total ball now in the urn= 33 red + 4 blue = 41

Hence the probability of drawing a blue ball at the fourth draw after drawing red balls at the previous attempts = 8/41

P(C4) = P ( fourth ball is blue ) * P( first ball red)*P(second ball red) *P(third ball red )

= (8/41) * (15/23) * (21/29)* (27/35) = 0.0711

8 0
3 years ago
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