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3 years ago

Consider circle E.AB26DEFWhat is the mBC ?mBCPlease help

Mathematics

1 answer:

RSB [31]3 years ago

8 0

Step-by-step explanation:

< AEB + < BEC = 180° {BEING LINEAR PAIR }

26° + < BEC = 180°

< BEC = 180° - 26°

< BEC = 154°

ARC BC = < BEC ( relation between arc and central angle)

Arc BC = 154°

Hope it will help :)

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Can someone pls give me an explanation and answer?

True [87]

Answer:

x=50

Step-by-step explanation:

It is a line so it should be 180 degrease. You already have two of the angles and to find the third (x) you just need to subtract them from 180. 180-105=75, and 75-25 is 50, so x is 50.

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3 years ago

Read 2 more answers

How do I factor the following equation in the link? It has been factored, but I need to know the steps.

Vlad [161]

Given

$2x^2-x-3=0$

How to factor

Solution

Step 1

Multiply the first and last costant

$-3\times2x^2=-6x^2$

Step 2

Write out all the pair factors of -6x^2

$\begin{gathered} -6x^2=-6x\text{ and x} \\ -6x^2=-x\text{ and 6x} \\ -6x^2=\text{ -3x and 2x} \\ -6x^2=\text{ -2x and 3x} \end{gathered}$

Step 3

Check for the pair, such that when you add you will get -x

$\begin{gathered} it\text{ is } \\ -3x+2x=-x \\ \therefore-3x,\text{ 2x} \end{gathered}$

Step 4

Replace -x with -3x+2x in the equation

$2x^2-3x+2x-3=0$

Step 5

Put them into brackets Since + is at the center no stress.

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Step 6

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Step 7

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1 year ago

Suppose Q-Mart plans to obtain information on a randomly selected sample of customers using each type of charge card, using equa

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Answer:

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4 years ago

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3 years ago

Temperature in degrees Fahrenheit is equal to 32 more than 9/5 times the temperature in degrees Celsius . One day the high tempe

bazaltina [42]

The high temperature is 35 degree celsius

<em><u>Solution:</u></em>

Given that, Temperature in degrees Fahrenheit is equal to 32 more than 9/5 times the temperature in degrees Celsius

Let "f" be the temperature in degree Fahrenheit

Let "c" be the temperature in degree celsius

Therefore,

Temperature in degrees Fahrenheit = 32 + $\frac{9}{5}$ times the temperature in degrees Celsius

$f = 32 + \frac{9}{5} \times c$

One day the high temperature in Edison. Nj was 95 degrees Fahrenheit

f = 95 ; c = ?

Substitute f = 95 in above equation

$95 = 32 + \frac{9c}{5}\\\\95=\frac{32 \times 5 +9c}{5}\\\\95 \times 5 = 160+9c\\\\475 = 160 + 9c\\\\9c = 475 - 160\\\\9c = 315\\\\c = 35$

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3 years ago

Consider circle E.AB26DEFWhat is the mBC ?mBCPlease help​

Consider circle E.AB26DEFWhat is the mBC ?mBCPlease help