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mariarad [96]
4 years ago
13

A scientist wants to study snails in an ecosystem. The snails move slowly and are incapable of traveling long distances. Which m

ethod would be most effective? Which method would be least effective? Use the information you put in the chart to explain your reasoning.
SAT
2 answers:
Anton [14]4 years ago
8 0

Answer: I don't know if it is a math or science question but i guess the reasonable answer would be to get a camera and record the snail from an angle and watch it times 2 so that you don't have to sit there and watch the snail for a long period of time. I hope this helped.

Explanation:

blondinia [14]4 years ago
6 0
Do you want math or science? but you should get something to record with but just at a angle and watch the vid more than once so you don’t have to keep watching a snail.
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Which is true about the compounds carbon monoxide (co) and carbon dioxide (co2)?
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Answer:

Carbon Dioxide (CO2) is a chemical compound consisting of one carbon atom and two oxygen atoms. ... Carbon Monoxide (CO) is a chemical compound which contains one carbon atom and one oxygen atom and is also a colourless and odourless gas. Unlike CO2, it is entirely human-made and is not naturally present in the atmosphere.

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3 years ago
the distribution of lengths of salmon from a certain river is approximately normal with standard deviation 3.5 inches. if 10 per
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Complete question;

<em>The distribution of lengths of salmon from a certain river is approximately normal with a standard deviation of 3.5 inches. If 10 percent of salmon are longer than 30 inches, which of the following is closest to the mean of the distribution? 26 inches A 28 inches B 30 inches C 33 inches D 34 inches</em>

Option B is correct. The value that is closest to the mean of the distribution is 30inches.

The formula for calculating the z-score is expressed as:

z=\frac{ x-\mu}{\sigma}

Given the following parameters

\sigma = 3.5\\x = 26in

If 10 percent of salmon are longer than 30 inches, then:

  • P(x>30) = 0.1

Using the z table to get the value corresponding to the mean area 0.1.

  • The required z-score will be -1.285

Substitute the resulting parameters into the formula to get the mean of the distribution.

z=\frac{x-\mu}{\sigma}\\-1.285=\frac{26-\mu}{3.5}\\-1.285 \times 3.5 = 26 - \mu\\ -4.4975 = 26 - \mu\\\mu = 26 + 4.4975\\\mu = 30.4975\\\mu \approx 30in

Hence the value that is closest to the mean of the distribution is 30inches.

Learn more here: brainly.com/question/15295437

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2 years ago
Two 99 percent confidence intervals will be constructed to estimate the difference in means of two populations, r and w. One con
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The option that describes the relationship between the two confidence intervals is; The width of I₈₁ will be¹/₉ the width of I₉

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The width of the confidence interval will be calculated from the formula;

W = 2Z(σ/√n)

where;

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σ is standard deviation

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For first sample;

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For second Sample;

W_i81 = 2Z(σ/√81)

W_i81 = ²/₉Zσ

Thus, we will have;

W_i9/W_i81 = (²/₃Zσ)/(²/₉Zσ)

W_i9/W_i81 = 9

W_i81 = ¹/₉W_i9

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During infancy, initial personality is referred to as temperament.

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