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azamat
3 years ago
14

le of 2.00 moles of nitric oxide (NO) gas was reacted withle of 2.00 moles of nitric oxide (NO) gas was reacted withle of 2.00 m

oles of nitric oxide (NO) gas was reacted withle of 2.00 moles of nitric oxide (NO) gas was reacted withle of 2.00 moles of nitric oxide (NO) gas was reacted withle of 2.00 moles of nitric oxide (NO) gas was reacted withle of 2.00 moles of nitric oxide (NO) gas was reacted withle of 2.00 moles of nitric oxide (NO) gas was reacted withle of 2.00 moles of nitric oxide (NO) gas was reacted withle of 2.00 moles of nitric oxide (NO) gas was reacted withle of 2.00 moles of nitric oxide (NO) gas was reacted with
Mathematics
2 answers:
Mrrafil [7]3 years ago
6 0

Answer:

it's too hard bro sorry bro

tresset_1 [31]3 years ago
4 0

Answer:

okay thank you for answering okay okay okay

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A 4f by 5ft dock is anchored in the middle of a lake. The bow of a boat is tied to a corner of the dock with a 5ft rope as shown
makvit [3.9K]
Is there a photo or something
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4 years ago
Pretzels are given away for free at a local store. The tray is constantly replenished as people take the pretzels.The number of
Tanzania [10]

Answer:

The answer is "-13.5 \ / minute \\\\"

Step-by-step explanation:

The average rate to the changes of pretzels form t= 1 \ minutes to t=1.5 \ minutes will be:

=\frac{P(1.5)-p(1)}{1.5-1}\\\\=\frac{(20+(1.5)^2- 8 \cos \pi (1.5))-(20+1^2 -8 \cos \pi)}{0.5}\\\\=\frac{22.25-29}{0.5}\\\\=\frac{-675}{50}\\\\=-13.5 \ / minute \\\\

7 0
3 years ago
Use the given information to find the p-value. also use a0.05 significance level and state the conclusion about the null hypothe
omeli [17]

Answer:

(a) C: 0.0465 ; reject the null hypothesis

(b) B: 0.3409 ; fail to reject the null hypothesis

Step-by-step explanation:

Firstly, the decision rule based on P-value to reject the null hypothesis or fail to reject the null hypothesis is given by;

  • If the P-value of test statistics is less than the level of significance, then we have sufficient evidence to reject our null hypothesis.
  • If the P-value of test statistics is more than the level of significance, then we have insufficient evidence to reject our null hypothesis due to which we fail to reject our null hypothesis.

(a) Now, we are given alternate hypothesis, H_1 : p < 3/5

Also, z test statistics is -1.68. Since this is a left tailed test, so P-value is given by;

             P-value = P(Z < -1.68) = 1 - P(Z \leq 1.68)

                           = 1 - 0.95352 = <u>0.0465</u>

Since, the P-value of test statistics is less than the level of significance as 0.0465 < 0.05, so we have sufficient evidence to reject our null hypothesis due to which <u>we reject the null hypothesis.</u>

(b) Now, we are given alternate hypothesis, H_1 : p > 0.383

Also, z test statistics is 0.41. Since this is a right tailed test, so P-value is given by;

             P-value = P(Z > 0.41) = 1 - P(Z \leq 0.41)

                           = 1 - 0.6591 = <u>0.3409</u>

Since, the P-value of test statistics is more than the level of significance as 0.3409 > 0.05, so we have insufficient evidence to reject our null hypothesis due to which <u>we fail to reject the null hypothesis.</u>

5 0
3 years ago
Which of the following are true statements using the Associative Property of Multiplication?
dangina [55]

Answer:

All of the following statements are true because the products, three or four numbers, remain the same regardless of how the numbers are grouped.

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3 years ago
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