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allsm [11]
3 years ago
15

A Ferris wheel is 25 meters in diameter and boarded from a platform that is 1 meter above the ground. The six o'clock position o

n the Ferris wheel is level with the loading platform. The wheel completes 1 full revolution in 10 minutes. The function h (t)gives a person's height in meters above the ground t minutes after the wheel begins to turn.a.Find the amplitude, midline, and period of h (t).b.Find a formula for the height function h (t).c.How high off the ground is a person after 5 minutes?
Mathematics
1 answer:
icang [17]3 years ago
3 0

Answer:

h(t) = -12.5cos(0.2\pi t)+ 13.5

h(5) = 26m meters above ground after 5 mins

Step-by-step explanation:

This is a fun question, it requires a bit of visualization and some familiarity with how circles relate to trigonometric functions.

Thinking process:

  • Ferris wheel is a circle
  • It's starts from the 6 o clock position (the ground)
  • the plot of h(t) will start from the 6 o clock position as well

This much information is enough for you to visualize that the plot for h(t) is a trigonometric function (since we're dealing with a circle).

And as the function is NOT starting from the center (i.e 3 o clock position) it is not a sine function.

so a cos function might do the trick! (think of y=cosx ) but remember that the ferris wheel will start from the ground, so y=-cosx ) is a better choice.

  • The diameter of the ferris wheel = 25m
  • Since its takes 10mins to do a complete revolution the Period = 10 minutes
  • rpm (revolution per minute) = \dfrac{1rev}{10rev} == 0.1\dfrac{rev}{min}
  • there's 1 meter gap between the ground and the ferris wheel.

Solution:

We can start with the plot of just a general cosine function but with the negative sign due to the reasons given above.

h = -Acos(Bt) + C

h is the height and since it is a function in terms of t. we can rewrite the function as

h(t) = -Acos(Bt) + C

here,

A = The Amplitude (distance from the midline to the peak, think of radius of a circle rather than the diameter)

B = Frequency (in \frac{radians}{unit\,of\,time} )

C = Distance of the midline from the x-axis

To covert these into values that are meaningful in our case

A = The radius of the ferris wheel (12.5 m)

B = rpm of the Ferris wheel converted into radians per second. i.e

\dfrac{0.1rev}{min} * \dfrac{2\pi radians}{1 rev}\\ 0.2\pi \dfrac{rad}{min}

B = 0.2\pi \dfrac{rad}{min}

C = since the ferris wheel is above ground at all times, the midline should be atleast be 12.5 meters away from the ground (i.e. radius) but since it is also specified that there's a 1 meter gap between the ground and the ferris wheel C should be:

C = 12.5 + 1  =13.5

Finally, just put all the values in the equation:

h(t) = -Acos(Bt) + C

h(t) = -12.5cos(0.2\pi t)+ 13.5

FInally, to find h(5)

h(t) = -12.5cos(0.2\pi (5))+ 13.5

h(t) = -12.5(-1)+ 13.5

h(t) = 26 meters above ground

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Two athletes practice for a marathon by running back and forth on a 11-mile course. They start running simultaneously, one at a
maks197457 [2]

Answer:

Faster runner speed: 11 mph

Slower runner speed: 9 mph

Distance from starting point: 9.9 miles

Step-by-step explanation:

Let the slower runner speed be: x

Faster runner speed: x+2

1 hour 6 minutes = 1.1 hours

Slower: 1.1(x) = 1.1x miles

Faster: 1.1(x+2) = 1.1x+2.2 miles

This means that the faster runner had gone 2.2 miles more than the slower runner.

1.1x + 2.2 > 11 miles (This is true as we know the faster runner is coming back from the 11 mile run)

1.1x > 11 - 2.2 miles

1.1x > 8.8 miles

x > 8.8 / 2.2 miles

x > 8 mph

1.1x < 11 miles (we know this is true as the slower runner has to have gone less than 11 miles as the faster runner met him on his way back)

x < 11 / 1.1 miles

x < 10 miles

8 < x < 10

Although x could be any number including decimal between 8 and 10, the obvious first answer would be 9. However we need to check if this answer is correct.

Slower runner distance to the end:

1.1(9) = 9.9 miles

11 - 9.9 = 1.1 miles

Faster runners distance from the end (when coming back)

1.1(9+2) = 1.1(11) = 12.1 miles

12.1 - 11 = 1.1 miles

The speeds 9 mph and 11 mph are now proven to be the right speeds. Using our equation before, we can figure out the distance from the starting point that they meet at. This is just how far the slower runner has gotten. So, 1.1(9) = 9.9 miles from the starting point

7 0
2 years ago
Can someone help me with this one?
Pavel [41]

Answer:

21/25 = 84/100

17/20 = 85/100

21/25 < 17/20

Step-by-step explanation:

∵ The common multiple of 25 and 20 is 100

∵ 100 ÷ 25 = 4

∴ 21/25 = (21 × 4)/(25 × 4) = 84/100

∵ 100 ÷ 20 = 5

∴ 17/20 = (17 × 5)/(20 × 5) = 85/100

∵ 84 < 85

∴ 84/100 < 85/100

∴ 21/25 < 17/20

4 0
3 years ago
If x = 3 and y = -1, then 3x2 + 2xy - 5 = ? <br> A: 18 <br> B: 24 <br> C: 12 <br> D: 16
iris [78.8K]
x = 3 , \ y = -1 \\ \\ 3x^2 + 2xy - 5 = 3\cdot 3^2 + 2\cdot 3\cdot (-1)-5=\\ \\=3\cdot 9 -6-5=27-11=16 \\ \\ Answer : \ D: \ \ 16


8 0
3 years ago
Read 2 more answers
A small garden has an area of 25 square yards. How long is each side of the garden? *
Marrrta [24]

Answer:

5

Step-by-step explanation:

4 0
2 years ago
Given an arithmetic sequence in the table below, create the explicit formula and list any restrictions to the domain.
djyliett [7]
An=a1+d(n-1)
an=nth term
a1=first term, when n=1
d=common differnce=amount each term increases by
n=which one


so
when n=1, an=40
so a1=40
it seems to increas by 7 each time

an=40+7(n-1)
explicit formula is expanded
an=40+7n-7
an=33+7n is the formula

the domain is natural numbers because you can't have the -3rd term or the 0th term or the 3.24th term

domain is natural numbers
the formula is a_n=33+7n or a_n=7n+33
6 0
3 years ago
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