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3 years ago

HELP!!!!! If anyone knows the answer please tell me as soon as possible PLEASE!!!!

Mathematics

2 answers:

worty [1.4K]3 years ago

7 0

Answer:

Plotting the points on graph and joining them gives a right angle triangle

Eddi Din [679]3 years ago

6 0

Answer:

right angle triangle

Step-by-step explanation:

Slope = (Y1-Y2)/(X1-X2)

The slope of AC is 1/3. The slope of BC is -3. Therefore AC is perpendicular to BC (right angle).

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charlotte is playing a beanbag toss game. she has a 10% chance of hitting the 3- point hole, a 30% chance of hitting the 1- poin

34kurt

Answer:

Step-by-step explanation:

The expected value of a toss is:

E(X) = (0.10) (3) + (0.30) (1) + (0.60) (0)

E(X) = 0.6

If she scores an average of 0.6 points per toss, then the expected number of tosses needed to get 12 points is:

12 / 0.6 = 20

Using a random number table, we can assign digit 0 as a 3-point hole, digits 1-3 as a 1-point hole, and digits 4-9 as no points. Read the digits and add the points until you get 12 points. The number of digits read is the number of beanbag tosses.

5 0

3 years ago

What is the solution of the equation?. 3^5√(x+2)^3+3=27

Serggg [28]

3 0

4 years ago

Which of the following graphs correctly represents: (pictures)

Aloiza [94]

The correct answer is: [A]:
______________________________________________________
{The first graph that is shown among the answer choices provided}:
______________________________________________________
→ shows: " x ≤ 3 " ; as follows:
______________________________________________________

5 0

3 years ago

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

3 years ago

I need someone to help me with my algebra homework :(

GrogVix [38]

Answer:

ok, what grade level? and you need to actually type the questions into here

4 0

3 years ago

Read 2 more answers