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kenny6666 [7]
3 years ago
11

charlotte is playing a beanbag toss game. she has a 10% chance of hitting the 3- point hole, a 30% chance of hitting the 1- poin

t hole, and a 60% chance of getting 0 points. how many bean bags should we expect to toss to get 12 points? describe how you will use a random number table to conduct this simulation
Mathematics
1 answer:
34kurt3 years ago
5 0

Answer:

20

Step-by-step explanation:

The expected value of a toss is:

E(X) = (0.10) (3) + (0.30) (1) + (0.60) (0)

E(X) = 0.6

If she scores an average of 0.6 points per toss, then the expected number of tosses needed to get 12 points is:

12 / 0.6 = 20

Using a random number table, we can assign digit 0 as a 3-point hole, digits 1-3 as a 1-point hole, and digits 4-9 as no points.  Read the digits and add the points until you get 12 points.  The number of digits read is the number of beanbag tosses.

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Yanka [14]

Answer:

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Remember that we must write the constraint as:

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Now, let's compute the partial derivations, those must be zero.

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Those must be equal to zero, then we have a system of equations:

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L(x, y, λ) = f(x, y) +  λ*g(x, y)

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x = y

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y + y - 196 = 0

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x*y = y*y = 98*98 = 9,604

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Answer:

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Step-by-step explanation:

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Citrus2011 [14]

Answer:

the third side is 4.

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