Question

charlotte is playing a beanbag toss game. she has a 10% chance of hitting the 3- point hole, a 30% chance of hitting the 1- point hole, and a 60% chance of getting 0 points. how many bean bags should we expect to toss to get 12 points? describe how you will use a random number table to conduct this simulation

Answer 1

Answer:

20

Step-by-step explanation:

The expected value of a toss is:

E(X) = (0.10) (3) + (0.30) (1) + (0.60) (0)

E(X) = 0.6

If she scores an average of 0.6 points per toss, then the expected number of tosses needed to get 12 points is:

12 / 0.6 = 20

Using a random number table, we can assign digit 0 as a 3-point hole, digits 1-3 as a 1-point hole, and digits 4-9 as no points.  Read the digits and add the points until you get 12 points.  The number of digits read is the number of beanbag tosses.