Mikayla evaluated the expression 0.86 times 23.4 using the steps shown below.

What is 7^5 equal to

Alona [7]

The answer to 7^5 = 16807

5 0

3 years ago

Explain why x^2 = -81 does not have a solution.

Evgesh-ka [11]

Remember, the graph of a line represents every point that is a possible solution for the equation of that line. So when the graphs of two equations cross, the point of intersection lies on both lines, meaning that it is a possible solution for both equations. When the graphs of two equations never touch, there are no shared points and there are no possible solutions for the system. When the graphs of two equations lie on top of one another, they share all their points and every one is a possible solution.

6 0

3 years ago

WE GIVE 11 POINTS AND BRAINIEST URGENT HELP

Alina [70]

Answer:

1. Find < ACB

2. Use that triangles =180 to find <B = 41

Step-by-step explanation:

1.We need to find < ACB

<ACB +<DBC= 180 They make a straight line

Subtract DBC from each side

<ACB = 180 - <DBC

We know DCB = 113

ACB = 180 -113

ACB = 67

2.The three angles of a triangle = 180, so we can then find <B

<A +<B + <ACB = 180

72 + B + 67 = 180

Combine like terms

139+ <B = 180

Subtract 139 from each side

<B = 180-139

<B =41

3 0

4 years ago

Read 2 more answers

1).Calculate T, when sample mean is 120, population mean is 100, standard deviation is 20 and smaple size is 10 using levels of

Sonbull [250]

Answer:

$t=\frac{120-100}{\frac{20}{\sqrt{10}}}=3.16$

$p_v =2*P(t_{9}>3.16)=0.012$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we can reject the null hypothesis, and the true mean is significantly different from 100 at 5% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=120$ represent the sample mean

$s=20$ represent the standard deviation for the sample

$n=10$ sample size

$\mu_o =100$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is different from 100, the system of hypothesis would be:

Null hypothesis: $\mu = 100$

Alternative hypothesis: $\mu \neq 100$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{120-100}{\frac{20}{\sqrt{10}}}=3.16$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=10-1=9$

Conclusion

Since is a tao tailed test the p value would be:

$p_v =2*P(t_{9}>3.16)=0.012$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we can reject the null hypothesis, and the true mean is significantly different from 100 at 5% of significance.

8 0

3 years ago

Read 2 more answers

The 128 employees of a company volunteer 12,480 hours in 26 weeks. On average, how many hours do they all volunteer per weeks? O

Orlov [11]

How many hours will they volunteer per weeks will be answered by dividing 12,480 and 26 which equals 480....On average, how many hours does each employee volunteer per week will be answered by dividing 12,480 by 128 which equals 97.5...Please mark brainliest...

5 0

3 years ago