All categories

3 years ago

Help please and thank you

Mathematics

1 answer:

Lelu [443]3 years ago

7 0

Answer: 30 posts

Step-by-step explanation:

each post is 5 feet apart and 30 x 2 + 45 x 2 = 150 which divided by 5 is 30

You might be interested in

The sum of three consecutive odd numbers is 75. what is the smallest of these numbers,n?

vlabodo [156]

Let x equal the lowest of the 3 consecutive odd integers:
(x) + (x + 2) + (x + 4) = 75
Combine like terms:
3x + 6 = 75
-6 -6
3x = 69
/3 /3
x = 23
The lowest integer is 23. The 3 integers, therefore, are 23, 25, and 27.
Hope this helps!
~ArchimedesEleven

4 0

3 years ago

Read 2 more answers

Solve for X 3x - 2 = 8x - 32

Nataliya [291]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

13.) Describe and correct the error in solving the equation.

Julli [10]

I think you’d have to multiply both sides to the equation by 10

So that’d make it 2x + 5 = 10

2x = 10 - 5
x = 5/2

Hope this helps

6 0

3 years ago

The distance covered by the fastest high-speed train in Japan traveling at maximum speed is represented on the graph. The fastes

andrew-mc [135]

Answer:

we need to see the graph to answer, but if you know how to find the slope, then you can compare them

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Examination, 152 Candidates offered Agriculture

agasfer [191]

SOLUTION

Given the question in the image, the following are the solution steps to answer the question

STEP 1: Write the given details

$n(G)=136,n(P)=128,n(A)=152,n(A\cap G)=52,n(A\cap P)=60,n(A\cap P\cap G)=30,n(P\cap G)=58$

STEP 2: Get the number of students that takes the subjects only

From the basic stuff, we have Number of candidates who had taken only each of the subjects

$\begin{gathered} n(A\text{ only)=}n(A)-\lbrack n(A\cap P)+n(A\cap G)-n(A\cap P\cap G)_{}\rbrack \\ \Rightarrow152-\lbrack52+60-30\rbrack=152-82=70 \\ \\ n(G\text{ only)=}n(G)-\lbrack n(A\cap G)+n(P\cap G)-n(A\cap P\cap G)\rbrack \\ \Rightarrow136-\lbrack52+58-30\rbrack=56 \\ \\ n(P\text{ only)=}128-\lbrack58+60-30\rbrack=40 \end{gathered}$

STEP 3: Represent the values above on a Venn Diagram after getting the values

STEP 4: Find the total number of candidate that sat for the exam.

$\begin{gathered} We\text{ su}m\text{ all the numbers in the Venn diagram to get the total number of candidates that sat for the exam} \\ We\text{ have:} \\ 70+22+30+30+28+56+40=276 \end{gathered}$

Hence, the total number of candidates that sat for the exam is 276

5 0

1 year ago

Read 2 more answers

Help please and thank you​

Help please and thank you