Question

The sum of three consecutive odd numbers is 75. what is the smallest of these numbers,n?

Answer 1

$a,a+2,a+4-\ three\ odd\ numbers\\\\ a+a+2+a+4=75\\\\ 3a+6=75\ \ \ \ | subtract\ 6\\\\ 3a=69\ \ \ \ | divide\ by\ 3\\\\ a=23\\\\ The\ smallest\ number\ is\ 23.$

Answer 2

Let x equal the lowest of the 3 consecutive odd integers:
(x) + (x + 2) + (x + 4) = 75
Combine like terms:
3x + 6 = 75
       -6    -6
3x = 69
/3      /3
x = 23
The lowest integer is 23. The 3 integers, therefore, are 23, 25, and 27.
Hope this helps!
~ArchimedesEleven