All categories

3 years ago

The sum of three consecutive odd numbers is 75. what is the smallest of these numbers,n?

2 answers:

Natasha2012 [34]3 years ago

5 0

$a,a+2,a+4-\ three\ odd\ numbers\\\\
a+a+2+a+4=75\\\\
3a+6=75\ \ \ \ | subtract\ 6\\\\
3a=69\ \ \ \ | divide\ by\ 3\\\\
a=23\\\\
The\ smallest\ number\ is\ 23.$

vlabodo [156]3 years ago

4 0

Let x equal the lowest of the 3 consecutive odd integers:
(x) + (x + 2) + (x + 4) = 75
Combine like terms:
3x + 6 = 75
-6 -6
3x = 69
/3 /3
x = 23
The lowest integer is 23. The 3 integers, therefore, are 23, 25, and 27.
Hope this helps!
~ArchimedesEleven

You might be interested in

Find the simple interest on 3,750 in 5 years at 3% rate per annum.

GaryK [48]

Answer:

562.5

Step-by-step explanation:

i=?

p=3750

r=3*1/100=3/100

t=5 years

I=P*R*T

3750*5*3/100

=5625/100

=562.5

4 0

3 years ago

Which one is Correct...? 2+2=4, 2+2=10 or 2+2=22?

myrzilka [38]

Answer:

2+2=4

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Blake and two friends equally shared the cups of water shown in the picture.

3241004551 [841]

The answer would be c- 2/6

there are six cups total and three (blake plus two others) friends

there are two ways you can solve this…

1. by making groups
if you look at the picture, you can split it into three groups because that is the number of people, then count how many cups there are in one group which will be your numerator for the denominator six which is the total

2. simple division
divide the total number of cups buy the number of people which is 3
you get two and follow the same process above

6 0

2 years ago

A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distri

nlexa [21]

Answer:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

For this case we want to test:

H0: Absenteeism is distributed evenly throughout the week

H1: Absenteeism is NOT distributed evenly throughout the week

We have the following data:

Monday Tuesday Wednesday Thursday Friday Saturday Total

12 9 11 10 9 9 60

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{60}{6}= 10$ and the expected value is the same for all the days since that's what we want to test.

now we can calculate the statistic:

$\chi^2 = \frac{(12-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(11-10)^2}{10}+\frac{(10-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(9-10)^2}{10}=0.8$

Now we can calculate the degrees of freedom (We know that we have 6 categories since we have information for 6 different days) for the statistic given by:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

4 0

3 years ago

Translate this word sentence to mathematical symbols: a. Three more than twice a number

maxonik [38]

2x+3=2

Correct me if I'm wrong.

7 0

3 years ago

Read 2 more answers