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We can draw a right triangle to easily visualize the given problem. Since the ski jumper is 2650 ft from the base of the ski jump, we can consider this as one of the right triangle's legs.
What we're looking for is the height of the ski jump or the other leg of the right triangle. Since the ski jumper looks up at an angle of elevation of 26°, we can use the tangent function to find the missing height. You may refer to the image below to better understand the problem.
Recall that tanθ = (opposite side facing the angle)/(side adjacent to the angle). For this case, we have
Hence, the height of the ski jump (rounded off the nearest whole foot) is 1292 feet.
Answer: 1292 feet
What we're looking for is the height of the ski jump or the other leg of the right triangle. Since the ski jumper looks up at an angle of elevation of 26°, we can use the tangent function to find the missing height. You may refer to the image below to better understand the problem.
Recall that tanθ = (opposite side facing the angle)/(side adjacent to the angle). For this case, we have
Hence, the height of the ski jump (rounded off the nearest whole foot) is 1292 feet.
Answer: 1292 feet
Answer:
20 units²
Step-by-step explanation:
The x-intercepts are symmetrically located around the x-coordinate of the vertex, so are at
1.5 ± 5/2 = {-1, 4}
Using one of these we can find the unknown parameter "a" in the parabola's equation (in vertex form) ...
0 = a(4 -1.5)² +12.5
0 = 6.25a +12.5 . . . . . simplify
0 = a +2 . . . . . . . . . . . divide by 6.25
-2 = a
Then the standard-form equation of the parabola is ...
y = -2(x -1.5)² +12.5 = -2(x² -3x +2.25) +12.5
y = -2x² +6x +8
This tells us the y-intercept is 8. Then the relevant triangle has a base of 5 units and a height of 8. Its area is given by the formula ...
A = (1/2)bh = (1/2)(5)(8) = 20 . . . . units²
