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3 years ago

Please help me will mark brainliest

Mathematics

1 answer:

MAVERICK [17]3 years ago

6 0

Answer:

-20

-12

Step-by-step explanation:

g(4)

= 4(4)-12

= 16-12

= 4

g(-2)

=4(-2)-12

=-8-12

=-20

g(0)

=4(0)-12

=0-12

=-12

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Whats The sum of twice a number x and thrice a number y minus the square of z as an expression

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Answer:

2x+3y-z²

Step-by-step explanation:

twice a number =2x

thrice a number =3x

minus z²

HOPE THIS HELPS!!!

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2 years ago

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The weight of 1000 identical samples is 1 pound. what is the weight of 10 samples

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1/100 of a pound.
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3 years ago

Find the extreme values of the function f(x, y) = 4x2 + 6y2 on the circle x2 + y2 = 1.

julia-pushkina [17]

Answer with Step-by-step explanation:

We are given that

$f(x,y)=4x^2+6y^2$

Let g(x,y)= $x^2+y^2=1$

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$\nabla f(x,y)$

$\nabla g(x,y)=$

Using Lagrange multipliers

$\nabla f(x,y)=\lambda \nabla g(x,y)$

$f_x=\lambda g_x$

$8x=\lambda 2x$

Possible value x=0 or $\lambda=4$

If x=0 then substitute the value in g(x,y)

Then, we get $y=\pm 1$

$f_y=\lambda g_y$

$12y=\lambda 2y$

If $\lambda=4$ and substitute in the equation

Then , we get possible value of y=0

When y=0 substitute in g(x,y) then we get

$x=\pm 1$

Hence, function has possible extreme values at points (0,1),(0,-1), (1,0) and (-1,0).

$f(0,1)=6$

$f(0,-1)=6$

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$f(-1,0)=4$

Therefore, the maximum value of f on the circle $x^2+y^2=1$ is $f(0,\pm1)=6$ and minimum value of $f(\pm1,0)=4$

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3 years ago

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Misha Larkins [42]

Answer:

C. $2.54/gallon

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To find the unit price, we take the dollar amount and divide by the number of gallons

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3 0

3 years ago

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Which of the following are solutions to the equation below?

nalin [4]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Let's solve the given equation ~

$\qquad \tt \dashrightarrow \:4 {x}^{2} + 20x + 25 = 49$

$\qquad \tt \dashrightarrow \:4 {x}^{2} + 20x + 25 - 49 = 0$

$\qquad \tt \dashrightarrow \:4 {x}^{2} + 20x - 24 = 0$

$\qquad \tt \dashrightarrow \:4( {x}^{2} + 5x - 6) = 0$

$\qquad \tt \dashrightarrow \: {x}^{2} + 5x - 6 = 0$

$\qquad \tt \dashrightarrow \: {x}^{2} + 6x - x - 6 = 0$

$\qquad \tt \dashrightarrow \:x(x + 6) - 1(x + 6) = 0$

$\qquad \tt \dashrightarrow \:(x + 6)(x - 1) = 0$

Hence, we get -6 and 1 as our roots ~

So, the correct choices are : B and D

3 0

2 years ago

Please help me will mark brainliest​

Please help me will mark brainliest