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dolphi86 [110]
3 years ago
14

Please help me will mark brainliest​

Mathematics
1 answer:
MAVERICK [17]3 years ago
6 0

Answer:

4

-20

-12

Step-by-step explanation:

g(4)

= 4(4)-12

= 16-12

= 4

g(-2)

=4(-2)-12

=-8-12

=-20

g(0)

=4(0)-12

=0-12

=-12

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Whats The sum of twice a number x and thrice a number y minus the square of z as an expression
SpyIntel [72]

Answer:

2x+3y-z²

Step-by-step explanation:

twice a number =2x

thrice a number =3x

minus z²

HOPE THIS HELPS!!!

8 0
2 years ago
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The weight of 1000 identical samples is 1 pound. what is the weight of 10 samples
Leno4ka [110]
1/100 of a pound.
since 1000/100=10, you must do 1/100 to get the weight of 10 samples.
6 0
3 years ago
Find the extreme values of the function f(x, y) = 4x2 + 6y2 on the circle x2 + y2 = 1.
julia-pushkina [17]

Answer with Step-by-step explanation:

We are given that

f(x,y)=4x^2+6y^2

Let g(x,y)=x^2+y^2=1

We have to find the extreme values  of the given function

\nabla f(x,y)

\nabla g(x,y)=

Using Lagrange multipliers

\nabla f(x,y)=\lambda \nabla g(x,y)

f_x=\lambda g_x

8x=\lambda 2x

Possible value x=0 or \lambda=4

If x=0 then substitute the value in g(x,y)

Then, we get y=\pm 1

f_y=\lambda g_y

12y=\lambda 2y

If \lambda=4 and substitute in the equation

Then , we  get possible value of y=0

When y=0 substitute in g(x,y) then we get

x=\pm 1

Hence, function has possible  extreme values at points (0,1),(0,-1), (1,0) and (-1,0).

f(0,1)=6

f(0,-1)=6

f(1,0)=4

f(-1,0)=4

Therefore, the maximum value of f  on the circlex^2+y^2=1  is f(0,\pm1)=6 and minimum value of f(\pm1,0)=4

7 0
3 years ago
Seth bought 18.4 gallons of gasoline for $46.74. What was the unit price of the gasoline?
Misha Larkins [42]

Answer:

C. $2.54/gallon

Step-by-step explanation:

To find the unit price, we take the dollar amount and divide by the number of gallons

$46.74/18.4

2.540217391

The unit price per gallon of gasoline is

$2.54/ gallon

3 0
3 years ago
Read 2 more answers
Which of the following are solutions to the equation below?
nalin [4]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve the given equation ~

\qquad \tt \dashrightarrow \:4 {x}^{2}  + 20x + 25 = 49

\qquad \tt \dashrightarrow \:4 {x}^{2}  + 20x + 25  -  49 = 0

\qquad \tt \dashrightarrow \:4 {x}^{2}  + 20x - 24 = 0

\qquad \tt \dashrightarrow \:4( {x}^{2}  + 5x - 6) = 0

\qquad \tt \dashrightarrow \: {x}^{2}  + 5x - 6 = 0

\qquad \tt \dashrightarrow \: {x}^{2}  + 6x - x - 6 = 0

\qquad \tt \dashrightarrow \:x(x + 6) - 1(x + 6) = 0

\qquad \tt \dashrightarrow \:(x + 6)(x - 1) = 0

Hence, we get -6 and 1 as our roots ~

So, the correct choices are : B and D

3 0
2 years ago
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