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3 years ago

Pls help ill mark brainliest

Mathematics

1 answer:

Dmitry_Shevchenko [17]3 years ago

5 0

Answer:

Ruled,Trade expeditions,and trade center

Step-by-step explanation:

I hope it helps

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Denzel can mow 1/8 of his yard every 7 minutes. If he had 40 minutes to mow 3/4 of the yard, will he have enough time

ehidna [41]

Answer:

No. He is short by 2 minutes

Step-by-step explanation:

Given that Denzel can mow 1/8 of his yard every 7 minutes.

Hence he can mow the full yard in 7(8) = 56 minutes.

Now he has to do 3/4 of his yard and time is 40 minutes

For 3/4 of yard time taken would be = 3/4 (56) = 42 minutes.

If he had 40 minutes to mow 3/4 of the yard, he will not have enough time since he is short of time by 2 minutes.

8 0

3 years ago

23.41/3.1 ESTIMATE PLEAS

sergeinik [125]

Answer:

Step-by-step explanation:

8 0

3 years ago

Cells use the hydrolysis of adenosine triphosphate, abbreviated as ATP, as a source of energy. Symbolically, this reaction can b

nataly862011 [7]

Answer:

Step-by-step explanation:

From the given information:

ΔG° = -30.5 kJ/mol

By applying the following equation to calculate the value of K.

ΔG° =-RT㏑K

making ㏑ K the subject of the formula:

$\mathtt{ In \ K} = \dfrac{\Delta G^0}{-RT}$

where;

Temperature at 25° C = (25 + 273)K

= 298K

R = 8.3145 J/mol.K (gas cosntant)

$\mathtt{ In \ K} = \dfrac{-30.5 \times 10^{3}\ J /mol} {-(8.3145 \ J/mol. K \times 298 \ K}$

$\mathtt{ In \ K} = \dfrac{-30.5 \times 10^{3}\ J /mol} {-2477.721 J/mol }$

㏑K = 12.309

$K = e^{12.309}$

K = 221682.17

K = 2.22 × 10⁵

b) The reaction for the metabolism of glucose is given as:

$C_6H_{12} O_6 + 6O_{2(g)} \to + 6CO_{2(g)} + 6H_2O_{(l)}$

From the above expression, let calculate the Gibbs free energy by using the formula:

$\Delta G^0_{rx n }= \Delta G^0_{product}- \Delta G^0_{reactant}$

$\Delta G^0_{rx n }= [6 \times \Delta G^0_{f}(CO_2) + 6 \times \Delta G^0_{f}(H_2O)] - [1 \times \Delta G^0_{f}(C_6H_{12}O_6) + 6 \times \Delta G^0_{f}(O_2)]$

At standard conditions;

The values of corresponding compounds are substituted into the equation above:

Thus,

$\Delta G^0_{rx n }= [6 \times (-394) + 6 \times (-237)] - [1 \times (-911) + 6 \times (0)] \ kJ/mol$

$\Delta G^0_{rx n }= [-2364-1422] - [-911+0] \ kJ/mol$

$\Delta G^0_{rx n }= -3786 +911 \ kJ/mol$

$\Delta G^0_{rx n }= -2875 \ kJ/mol$

$\Delta G^0_{rx n }= -2875000 \ J/mol$

Now, the no of ATP molecules generated = $\dfrac{\Delta G^0 \text{of metabolism for glucose}}{\Delta G^0 \text{of hydrolysis for ATP}}$

= (-2875000 J/mol ) / -30500 J/mol

= 94.26

≅ 94 ATP molecules generated

3 0

3 years ago

50pts!! Which expression is equivalent to the polynomial given below? 54x+30

Ostrovityanka [42]

Answer:

6(9x+5)

Step-by-step explanation:

6*9x = 54x

6*5 = 30

8 0

3 years ago

Read 2 more answers

The diameter of a circle is 3 meters. What is the circumference?

Gennadij [26K]

Answer:

C≈9.42m

Using any of this formulas

C=2πr

C=2πrd=2r

Solution:

C=πd=π·3≈9.42478m

3 0

3 years ago