Let c and n represent the numbers of pencil and pen boxes, respectively
.. 3c +2n = 6.00
.. 2c +4n = 8.00
You can halve the second equation and subtract it from the first to get
.. (3c +2n) -(c +2n) = 6.00 -4.00
.. 2c = 2.00
.. c = 1.00
Then
.. 1.00 +2n = 4.00 . . . . . half the original second equation with c filled n
.. 2n = 3.00
.. n = 1.50
A box of pencils costs $1.00; a box of pens costs $1.50.
Answer:
The answer is 4.35, rounded two decimals to hundredths place.
<em>some text here to make the answer slightly longer for some good reasons. yep.</em>
Step-by-step explanation:
3 tan 2x - 4 tan 3x = tan² 3x * tan 2x
3 (tan 2x - tan 3x) = tan 3x + tan² 3x * tan 2x
= tan 3x (1 + tan 3x * tan 2x)
3 (tan 2x - tan 3x)/(1 + tan 3x * tan 2x) = tan 3x
3 * (- tan x) = tan 3x
-3tanx = (3 tan x - tan³ x) / (1 - 3 tan² x)
3 - tan² x = - 3 + 9 tan² x
tan x = + √3 /√5 or - √3/√5
1 cup of oil would equal up to 8 fluid ounces
Given:
Anna’s cell phone plan charges her $30 per month plus a $150 one-time activation fee.
Evelyn’s cell phone plan charges her $20 per month, plus a $450 one-time activation fee.
To find:
The number of months after which the costs for the girls’ cell phone plans the same.
Solution:
Let x be the number of months.
Total cost = Fixed cost + Variable cost
According to the question, cost equation for Anna’s cell phone is
...(i)
Cost equation for Evelyn's cell phone is
...(ii)
Equate (i) and (ii) to find the time after which the costs for the girls’ cell phone plans the same.
Divide both sides by 10.
Therefore, the costs for the girls’ cell phone plans the same after 10 months.
