A circle of radius 1 is inscribed within a square. What is the probability that a randomly-selected point with the square is also within the circle?
Step-by-step explanation:
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Answer:
x = -1
Step-by-step explanation:
3(x+1) = -2(x-1) - 4
3x + 3 = -2x + 2 - 4
3x + 3 = -2x - 2
Add the -2x to both sides
5x + 3 = -2
Subtract the 3 to both sides
5x = -5
Divide both sides by 5
x = -1
Answer:
b is 0
Step-by-step explanation:
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Answer:
Step-by-step explanation:
Hello,
degree 5
4 is a zero of multiplicity 3 -> (x-4)^3 is a factor
-4 is the only other zero, so the multiplicity is 5-3=2 -> (x+4)^2 is a factor
leading coefficient is 4 so we can write
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