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2 years ago

Find the sum of QR 4x+33

Mathematics

1 answer:

12345 [234]2 years ago

4 0

Answer:

Step-by-step explanation:

Simplifying

4x + 5 = 33

Reorder the terms:

5 + 4x = 33

Solving

5 + 4x = 33

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5' to each side of the equation.

5 + -5 + 4x = 33 + -5

Combine like terms: 5 + -5 = 0

0 + 4x = 33 + -5

4x = 33 + -5

Combine like terms: 33 + -5 = 28

4x = 28

Divide each side by '4'.

x = 7

Simplifying

x = 7

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NeX [460]

The answer to the questions

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3 years ago

PLEASE HELP ME!! Kevin earns a base salary of $350.00 every week with an additional 12%

Mrrafil [7]

<h3>Answer: 944 dollars for the week</h3>

============================================================

Explanation:

He sold $4950 worth of items. Take 12% of this amount to get

12% of 4950 = 0.12*4950 = 594

So he earns $594 in commission on top of the $350 base salary paid every week. In total, he earns 594+350 = 944 dollars for that week

This isn't the per week pay because he would need to sell exactly $4950 worth of goods each week to keep this same weekly pay.

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2 years ago

A while back, either James borrowed $12 from his friend Rita or she borrowed $12 from him, but he can’t quite remember which. Ei

Vadim26 [7]

Answer:

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Step-by-step explanation:

He's either gaining or losing $12 so you can write 42.8 plus or minus 12 as the equation

6 0

3 years ago

How to prove this???

swat32

$\cos^3 2A + 3 \cos 2A \\
\Rightarrow \cos 2A (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ 
\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) 
$

go to right side now

$4( \cos^6 A - \sin^6 A)\\
\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)$

use $x^3 - y^3 = (x-y)(x^2 + xy + y^2)$ and $x^3 + y^3 = x^2 - xy + y^2$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\
\Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\
~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)$

so $\sin^2 A + \cos^2 A = 1$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\
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2 years ago

50 multiplied by 100

ra1l [238]

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2 years ago