Answer:
$6,400
Step-by-step explanation:
9100-1100
8000
8000×1/5
$1600
8000-1600
$6,400
Answer:
x > -3
Step-by-step explanation:
-3x + 6 < 15
-3x < 15 - 6
-3x < 9
-x < 3
x > -3
A= 360
B= 2(12)²(7)/120= 2016/120=16.8
Answer: (a) 0.006
(b) 0.027
Step-by-step explanation:
Given : P(AA) = 0.3 and P(AAA) = 0.70
Let event that a bulb is defective be denoted by D and not defective be D';
Conditional probabilities given are :
P(D/AA) = 0.02 and P(D/AAA) = 0.03
Thus P(D'/AA) = 1 - 0.02 = 0.98
and P(D'/AAA) = 1 - 0.03 = 0.97
(a) P(bulb from AA and defective) = P ( AA and D)
= P(AA) x P(D/AA)
= 0.3 x 0.02 = 0.006
(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)
= P(AA) x P(D/AA) + P(AAA) x P(D/AAA)
= 0.3(0.02) + 0.70(0.03)
= 0.027
