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3 years ago

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austin ran "a" miles. joshua ran at least one more than 3 times the number of miles that austin ran. write an inequality that co

uld be used to represent the number of miles joshua "j" ran

1 answer:

Mnenie [13.5K]3 years ago

7 0

3a > a is the inequality

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Does this graph show a function? Explain how you know.

Solnce55 [7]

ANSWER

C. Yes; the graph passes the vertical line test.

EXPLANATION

The quickest way to determine whether a graph represents a function or not is to perform the vertical line test.

If the graph passes the vertical line test, the graph represents a function.

If we draw vertical line across the graph in the attachment, it will touch the graph at one and only one point.

Since the graph passes the vertical line test, it represents a function.

7 0

3 years ago

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Can anybody help me please

klio [65]

Answer:

x y

0 -1

-1 0

-8 7

Step-by-step explanation:

y = -x - 1

when x = 0, y = -1

when y = 0

0 = -x - 1

x = -1

when x = -8,

y = -(-8) - 1

y = 7

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3 years ago

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4/7 - x = 6/35 what is x? how do I determine the answer?

vivado [14]

4/7 - x = 6/35

You're trying to get x by itself, so you have to subtract 4/7 from both sides.

-x = 6/35 - 4/7

You need both of the fractions to the right of the equal sign to have the same denominator so that we could simplify them, so multiply 5/5 to -4/7.

-4 /7 × 5/5 = -20/35

So, our new equation is :

-x = 6/35 - 20/35

Simplify.

-x = -14/35

Divide both sides by -1.

x = 14/35

Divide by 7.

x = 2/5

~Hope I helped!~

7 0

3 years ago

Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br

Lina20 [59]

Answer:

The differential equation for the amount of salt A(t) in the tank at a time t > 0 is $\frac{dA}{dt}=12 - \frac{2A(t)}{500+t}$ .

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

The concentration of the solution entering is 4 lb/gal.

Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

$\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t$

where, $\text{R}_i_n$ = concentration of salt in the inflow $\times$ input rate of brine solution

and $\text{R}_o_u_t$ = concentration of salt in the outflow $\times$ outflow rate of brine solution

So, $\text{R}_i_n$ = 4 lb/gal $\times$ 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

= 3 gal/min - 2 gal/min

= 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, $\text{R}_o_u_t$ = concentration of salt in the outflow $\times$ outflow rate of brine solution

= $\frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min}$ = $\frac{2A(t)}{500+t} \text{ lb/min }$

Now, the differential equation for the amount of salt A(t) in the tank at a time t > 0 is given by;

= $\frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }$

or $\frac{dA}{dt}=12 - \frac{2A(t)}{500+t}$ .

4 0

3 years ago

Help please - first question

Afina-wow [57]

The answer should be x=60. ABD are an equilateral triangle all the angles must add up to 180. 60*3=180. Also if you have a protractor you can measure the angle C, the 60 degrees part and measure it against A, D and B. Hope this helps.

5 0

3 years ago