Write the augmented matrix for the following system of equations. y + 2x = 0 -3x + 2y = -2

A small business employs 98 people. All of the employees work for 8 hours a day, 5 days a week. Eleven of the employees receive

GREYUIT [131]

98 people get $30 per hour, and 11 get an additional $15 per hour. Then the total payroll per hour is
.. $(98*30 +11*15) = $3105

So, the payroll for a 40-hour week is
.. 40*$3105 = $124,200

4 0

3 years ago

Read 2 more answers

Find the exact value by using a half angle identity.tan 75°

kramer

The trigonometric function is given as

$\tan 75^{\circ}$

Apply the half angle identity to find the value of tan 75 ,

$\tan (\frac{u}{2})=\frac{\sin u}{1+\cos u}$

Here,

$\tan (\frac{150^{\circ}}{2})=\frac{\sin150^{\circ}}{1+cos150^{\circ}}$ $\tan (75^{\circ})=\frac{\frac{1}{2}}{1-\frac{\sqrt[]{3}}{2}}=\frac{\frac{1}{2}}{\frac{2-\sqrt[]{3}}{2}}^{}$ $\tan 75^{\circ}=\frac{1}{2-\sqrt[]{3}}$

Now rationalize the function.

$\tan 75^{\circ}=\frac{1}{2-\sqrt[]{3}}\times\frac{2+\sqrt[]{3}}{2+\sqrt[]{3}}=\frac{2+\sqrt[]{3}}{4-3}=\frac{2+\sqrt[]{3}}{1}$

Again simplify the trigonometric function,

$\tan 75^{\circ}=2+1.732=3.732$

Hence the answer is 3.732.

5 0

1 year ago

Use the Special Right Triangle to evaluate sin 60°, cos 60° and tan 60°. Your answers should be exact (not a decimal).

soldier1979 [14.2K]

Sin(60) = ¹/₂√3
cos(60) = ¹/₂
tan(60) = √3

The answer is D.

4 0

2 years ago

Read 2 more answers

Jason is pulling a box across the room. He is pulling with a force of 19 newtons and his arm is making a 30 angle with the horiz

Cerrena [4.2K]

We are to solve for the vertical and horizontal component of the force he is pulling with.

1. The vertical component of Jason's force is 9.5Newtons.

2.The horizontal component of Jason's force is 2.67Newtons.

3. Therefore, the net force in the vertical direction is -12.5Newtons.

4.Therefore, Resultant, R is 72.11

Question 1:

If Jason is pulling with a force of 19 Newtons and his arm is at an angle of 30° with the horizontal.

By resolving Jason's force of pull in the vertical direction, Fy = 19 × Sin 30° = 9.5 Newtons.

The vertical component of Jason's force is 9.5 Newtons.

Question 2:

Also,If Jason is pulling with a force of 14 Newtons and his arm is at an angle of 79° with the horizontal.

By resolving Jason's force of pull in the horizontal direction, Fx = 14 × Cos79° = 2.67 Newtons.

The horizontal component of Jason's force is 2.67Newtons.

Question 3:

If Jason is pulling with a force of 23Newtons and his arm is at an angle of 30° with the horizontal.

By resolving Jason's force of pull in the vertical direction, Fy = 23 × Sin 30° = 11.5Newtons.

The vertical component of Jason's force of pull is, 11.5Newtons.

If the box weighs 24Newtons.

By treating up as the +ve vertical direction and down as the -ve vertical direction,

Therefore, the weight of the box acts in the -ve vertical direction, while Jason's vertical force component acts in the +ve vertical direction.

Therefore, the net force in the vertical direction is = 11.5Newtons + (-24Newtons)

Therefore, the net force in the vertical direction is -12.5Newtons.

Question 4:

If there are two forces at right angles to eachother, one of magnitude, 68 and the other of magnitude, 24.

The resultant force on the object can be obtained by Pythagoras theorem (Triangle law of forces).

Resultant, R = √(68²+24²) = √5200.

Therefore, Resultant, R = 72.11