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suter [353]
3 years ago
7

Sam lives 8 miles from work and Mike lives 30 miles from work how much farther is my stretchy work then Sam’s

Mathematics
1 answer:
Blizzard [7]3 years ago
3 0

Answer:

22 miles

Step-by-step explanation:

if i am reading this question correctly you are asking how much farther mike lives from sam.

30-8=22

this is pretty easy, just simple subtraction.

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Question 2(Multiple Choice Worth 1 points)<br> (01.04 LC)<br><br> Solve for x: −2x − 4 &gt; 8
frutty [35]

The required solution of the inequality is x  < - 6.


Given that,
To solve the equation −2x − 4 > 8.

<h3>What is inequality?</h3>

Inequality can be described as the consideration of the equation including the symbol of ( ≤, ≥, <, >) instead of the equal sign in an equation.


Here,
The given equation
−2x − 4 > 8
adding 4 on both sides
-2x > 12
multiply by -1
when multiplying the negative -1 it will change the behavior of the inequality, so.
2x < - 12
Divide by 2 into both sides
x < - 6

Thus, the required solution of the inequality is x  < - 6.

Learn more about inequality here:

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8 0
2 years ago
What fraction of the American flag is blue? Explain.
oksian1 [2.3K]
1/3 half of it is going with the stars
8 0
3 years ago
An airplane departs airport A at a heading of 300 (N 60 W). After traveling 320 miles, the airplane adjusts its course to 350 (N
iris [78.8K]

The shortest distance between the airport A and airport B travels by airplane which departs airport A at a heading of 300 (N 60 W) is 401 miles.

<h3>What is the law of cosine?</h3>

When the two sides of and one angle is known, then to find the third side, the law of cosine is used.

It can be given as,

c^2=a^2+b^2-2ab\cos C\\a^2=c^2+b^2-2ab\cos A\\b^2=a^2+c^2-2ab\cos B

Here, a,b and c are the sides of the triangle and A,B and C are the angles of the triangle.

An airplane departs airport A at a heading of 300 (N 60 W). After traveling 320 miles, the airplane adjusts its course to 350 (N 10 W) and flies an additional 112 miles to reach airport B.

The image of this problem is attached below. In this image, the two sides 112 miles and 320 miles are shown and the angle between them is 130 degrees. Thus, the value of x is,

x=\sqrt{112^2+130^2-2(112)(130)\cos 130^o}\\x=401\rm\; miles

Hence, the shortest distance between the airport A and airport B travels by airplane which departs airport A at a heading of 300 (N 60 W) is 401 miles.

Learn more about the law of cosine here;

brainly.com/question/4372174

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6 0
3 years ago
Helppppp 10points plz
ale4655 [162]

What is the question?

6 0
4 years ago
Peter runs laps on the school track every afternoon. He wants to run no more than 60 minutes a day. He can consistently run each
abruzzese [7]

Answer:

1.5x ≤ 60

Step-by-step explanation:

He wants to run no more than 60 minutes a day

No more than means Less than or equal to with the inequality sign of ≤

Each lap = 1.5 minutes.

The greatest number of laps Peter could run = x

Therefore, the inequality that best represents the situation and represents x, the greatest number of laps Peter could run in a day

1.5 × x ≤ 60 minutes

= 1.5x ≤ 60

Solving for x

1.5x ≤ 60

x ≤ 60/1.5

x ≤ 40 laps

Hence, the Greatest number of laps = x that he can run is 40 laps

4 0
3 years ago
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