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viva [34]
3 years ago
15

The combination for a lock uses three of the digits 1, 2, 3, and 4. How many three-digit combinations can the lock have? Explain

your answer.
Mathematics
1 answer:
Elenna [48]3 years ago
3 0

Answer:

24

Step-by-step explanation:

First you start by writing down all the combinations that start with each number. Then you just write the left over numbers and you'll end up with 24 because the is six of each starting number. Ex: 123, 132, 134, 143, 124, 142...

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NEED HELP BRANLIEST TO FIRST ANSWER
Juliette [100K]

Answer:

B

Step-by-step explanation:

3 0
3 years ago
While Playing Yahtzee and rolling 5 dice, Mei gets the result shown at right (the numbers are 2, 4, 4, 4, and 1). Mei decides to
Elina [12.6K]
A. The probability is 1/36. There are 36 combinations of the first and second dice and only one of them is 2 - 4s.

B. 10/36. Ten of the options contain exactly 1 - 4. 

C. The remaining 25/36 options do not include a 4. 
5 0
3 years ago
In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t 2 , 2 + t − 5t 2 , 1 + 2t} to the standard basis of P2.
Serjik [45]

Complete Question:

In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t² , 2+t− 5t² , 1 + 2t} to the standard basis C = {1, t, t²}. Then, write t² as a linear combination of the polynomials in B.

Answer:

The change of coordinate matrix is :

M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

Step-by-step explanation:

Let U =  {D, E, F} be any vector with respect to Basis B

U = D [1 − 3t²] + E [2+t− 5t²] + F[1 + 2t]..............(*)

U = [D+2E+F]+ t[E+2F] + t²[-3D-5E]...................(**)

In Matrix form;

\left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right] \left[\begin{array}{ccc}D\\E\\F\end{array}\right] = \left[\begin{array}{ccc}D+2E+F\\E+2F\\-3D-5E\end{array}\right]

The change of coordinate matrix is therefore,

M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]

To find D, E, F in (**) such that U = t²

D + 2E + F = 0.................(1)

E + 2F = 0.........................(2)

-3D -5E = 1........................(3)

Substituting eqn (2) into eqn (1 )

D=3F...................................(4)

Substituting equations (2) and (4) into eqn (3)

-9F+10F=1

F = 1

Put the value of F into equations (2) and (4)

E = -2(1) = -2

D = 3(1) = 3

Substituting the values of D, E, and F into (*)

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

3 0
3 years ago
4x/5 - 3x/7 = 4x/7 + 5x/7 can anyone please help with explanation...​
kirill115 [55]

Answer: x=0

Step-by-step explanation:

Multiply both sides of the equation by 35, the least common multiple of 5,7.

7×4x−5×3x=5×4x+5×5x

Multiply 7 and 4 to get 28.

28x−5×3x=5×4x+5×5x

Multiply −5 and 3 to get −15.

28x−15x=5×4x+5×5x

Combine 28x and −15x to get 13x.

13x=20x+25x

Combine 20x and 25x to get 45x.

13x=45x

Subtract 45x from both sides

13x−45x=0

Combine 13x and −45x to get −32x

−32x=0

Product of two numbers is equal to 0 if at least one of them is 0. Since −32 is not equal to 0, x must be equal to 0.

X=0

7 0
3 years ago
If y=9 when x=7 find y when x=2?
PilotLPTM [1.2K]
Is that all the information? it could literally be any number with only that.
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3 years ago
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