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3 years ago

Please help! 30 points!

Mathematics

2 answers:

djverab [1.8K]3 years ago

5 0

Answer:

((6 x 3 + 4/2) x 5 ) / 1

just olya [345]3 years ago

4 0

Okay so after trying this for almost half an hour this is what I got !

Answer:

(5 ÷1) ((4−2)+(6x3))

I think I used all of the operations; if you follow PEMDAS you should end up with 100 !

(5 ÷1) ((4−2)+(6x3))

(5) (2+18)

5(20)

100

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Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

$P(0) =\frac{1200}{12}$

$P(0) = 100$

Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

5 0

3 years ago

The Scott family is trying to save as much money as possible. One way to cut back on the money they spend is by finding deals wh

avanturin [10]

Answer:

Unit price of strawberries at Grocery Mart is $ 1.495 or 150 pennies

Unit price of strawberries at Baldwin Hills Market is $ 1.33 or 133 pennies.

Step-by-step explanation:

1 dollar = 100 pennies

Given:

Cost of 2 pounds of strawberries at Grocery Mart = $ 2.99

Cost of 3 pounds of strawberries at Baldwin Hills Market = $3.99

∵ Cost of 2 pounds of strawberries at Grocery Mart = $ 2.99

∴ Cost of 1 pound of strawberries at Grocery Mart = $\frac{2.99}{2}=\$1.495=1.495\times 100\approx 150\textrm{ pennies}$

∵ Cost of 3 pounds of strawberries at Baldwin Hills Market = $3.99

Cost of 1 pound of strawberries at Baldwin Hills Market = $\frac{3.99}{3}=\$1.33= 1.33\times 100 = 133\textrm{ pennies}$

Therefore, the unit price of strawberries at each grocery store is the cost of 1 pound of strawberries. So, unit rate at Grocery Mart is 150 pennies and at Baldwin Hills Market is 133 pennies.

7 0

3 years ago

Prove algebraically that 0.8 =8/9

-BARSIC- [3]

100x = 88.8888888.....

x = 0.8888888....

99x = 80

X = 80/99 = 0.8...

4 0

4 years ago

In order to be invited to tutoring or extension activities, a student's performance must be at least 20 points higher or lower t

marissa [1.9K]

Answer:

The inequality that represents p are p $\geq$ 125 or p $\leq$ 85.

Step-by-step explanation:

We are given that in order to be invited to tutoring or extension activities, a student's performance must be at least 20 points higher or lower than an average score. The average score is 105.

Let p = the scores for students who are eligible for tutoring or extension activities.

<u>The first condition</u> states that a student's performance must be at least 20 points higher than an average score, that means;

p $\geq$ (105 + 20)

p $\geq$ 125

Similarly, <u>the second condition</u> states that a student's performance must be at least 20 points lower than an average score, that means;

p $\leq$ (105 - 20)

p $\leq$ 85

So, the inequality that represents p are p $\geq$ 125 or p $\leq$ 85.

4 0

3 years ago

Read 2 more answers

How to graph (x-2)(y-3)=0

kolbaska11 [484]

Step-by-step explanation:

here you want to isolate the y.

so what you do in the beginning is divide both sides by x-2.

then, you'll have y-3 = 0

so y = 3

this is a horizontal graph that crosses the y axis and y = 3.

5 0

2 years ago