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Zarrin [17]
3 years ago
5

Subtract the polynomial

Mathematics
2 answers:
Artist 52 [7]3 years ago
8 0
Here’s the written one hope it helps

disa [49]3 years ago
3 0

Answer:

Step-by-step explanation:

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Aliyah bought a car for $32,000. It is now worth $5000 less than half of what she purchased it for. To the nearest tenth of a pe
N76 [4]

Answer:

65.6% is the answer.........

4 0
3 years ago
Arnold records the number of chirps per minute (x) that crickets make
Sauron [17]

Answer:

X=0 the temperatures is 40

Step-by-step explanation:

y=1/4x +40

x=0

y=1/4*0+40

y=0+40

y=40

7 0
3 years ago
If y’all can help with this one it’s imagine 2 i’m trying to figure out
Sindrei [870]

Answer:

I think it would be D. I'm not sure but I think so. I thought C at first but (go to explanation)

Step-by-step explanation:

if image 1 is the original, then image 2 would be it reflected over the y axis

C says over the line y=0 which would be a horizontal line. x=0 would be a vertical line aka the y axis. I believe its D.

8 0
2 years ago
three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal
Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

=     x + x + (x + \frac{6}{5}) = \frac{27}{4}

=     3x + \frac{6}{5} = \frac{27}{4}

=     3x = \frac{27}{4} - \frac{6}{5}

( let's take the LCM of 4 and 5 = 20

=     3x = \frac{135}{20} - \frac{24}{20}

=     3x = \frac{111}{20}

=       x = \frac{111}{20} ÷ \frac{3}{1} = \frac{111}{20} × \frac{1}{3} = \frac{37}{20}

So, the weight of the equal bags are \frac{37}{20} and the weight of the third bag ( heavy one ) is \frac{37}{20} + \frac{6}{5} = \frac{37}{20} + \frac{24}{20} = \frac{61}{20}

1st bag =     \frac{37}{20} kg

2nd bag =  \frac{37}{20} kg

3rd bag =   \frac{61}{20} kg

Hope it helps...

7 0
3 years ago
If X=60, Y=25, and Z=65, what is the tangent of
LekaFEV [45]
Tangent is opposite/adjacent so it would 60/25 which simplifies to 12/5
8 0
3 years ago
Read 2 more answers
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