Answer:
3^x -2x +14
Step-by-step explanation:
I will assume you mean 3^x in the function f(x)
f(x) = 3^x+ 10
g(x) = 2x - 4
(f - g)(x) = 3^x+ 10 - (2x - 4)
Distribute the minus sign
= 3^x+ 10 - 2x + 4
= 3^x -2x +14
Answer: Joy types 2 1/2pages
Step-by-step explanation:
Number of pages typed by Trish= 3 1/3 pages
Number of pages typed by joy=3/4 as many pages as Trish=3/4 x 3 1/3 pages
=3/4 x 3 1/3
=3/4 x 10/3
=(30/12) ÷(3/3)
=10/4)÷(2/2)
=5/2=2 1/2
1) Angle T = 72°
Angle U = 54°
2) Angle M = 76°
Angle N = 76°
<em>Explanation</em><em>:</em><em> </em>
<em> </em> 1. Isosceles triangle (since 2 sides are equal)
Angle U = Angle S = 54° (equal sides of a traingle have equal angles)
angle U + angle S + angle T =180 (Angle sum Property)
54° + 54° + angle T = 180°
108 + angle T = 180°
Angle T = 180 - 108
= 72°
2. Isosceles triangle again (same properties)
angle L + angle M + angle N = 180
28 + angle M + angle N = 180
angle M + angle N = 180 - 28
angle M + angle N = 152
"angle M and N will be equal since it is
isosceles triangle"
so, 2x (M&N) = 152
x = 152 ÷ 2
= 76
therefore angle M = angle N = 76°
Answer:
Step-by-step explanation:
x is clearly 42° because WU is an angle bisector of YWZ (which is 84, and bisecting means half of 84, that is 42)
now, for m of WYL
notice, YLW = 90°
also, UWL = 42°
name the intersection point of YL and WU as O in your mind
Apply angle sum property of a triangle for triangle WOL
angle WOL + angle UWL + angle YLW = 180
angle WOL + 90 + 42 = 180
angle WOL = 180 - 132
angle WOL = 48
now focus on line LOY
since LOY is a line, the angles a line intersecting it forms a linear pair, i.e
angle WOL + angle YOW = 180
48 + YOW = 180
angle YOW = 132
Now, apply angle sum property for triangle YOW
angle YOW + angle YWO (x) + angle WYO (or WYL) = 180
132 + 42 + WYO (or WYL) = 180
WYO (or WYL) = 6°
ask me in the comments if you have any doubts in this
<span>You could set up the relation as a table of
ordered pairs. Then, test to see if each element in the domain is
matched with exactly one element in the range. If so, you have a function!</span>
