Question

A carton has a length of fraction 2 and 1 over 4 feet, width of fraction 1 and 3 over 5 feet, and height of fraction 2 and 1 over 3 feet. What is the volume of the carton?

Answer 1

Answer:

$\frac{42}{5}\text{ ft}^3$.

Step-by-step explanation:

We have been given that a carton has a length of fraction $2\frac{1}{4}$ feet, width of fraction $1\frac{3}{5}$ feet, and height of $2\frac{1}{3}$ feet. We are asked to find the volume of the carton.

The volume of carton will be product of length, width and height.

Let us convert mixed fractions into improper fractions as:

$2\frac{1}{4}=\frac{9}{4}$

$1\frac{3}{5}=\frac{8}{5}$

$2\frac{1}{3}=\frac{7}{3}$

$\text{Volume of the carton}=\frac{9}{4}\text{ ft}\times\frac{8}{5}\text{ ft}\times\frac{7}{3}\text{ ft}$

$\text{Volume of the carton}=\frac{3}{1}\times\frac{2}{5}\times\frac{7}{1}\text{ ft}^3$

$\text{Volume of the carton}=3\times\frac{2}{5}\times7\text{ ft}^3$

$\text{Volume of the carton}=\frac{42}{5}\text{ ft}^3$

Therefore, the volume of the carton is $\frac{42}{5}\text{ ft}^3$.

Answer 2

If its a Rectangular Prism you should just time all of them together and that would make 8 2 over 5