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SCORPION-xisa [38]
3 years ago
15

1. 4 less than q

Mathematics
1 answer:
RSB [31]3 years ago
5 0
1. Q-4
2. 5x-3
Hshdjdjdjsjdjjdndjdjdjdjjd
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Write the function AG(X) representing the area of the garden in terms of x.
k0ka [10]

The area of this rectangle is x*y. But, this problem requires that you represent the variable "y" in terms of "x" only.

A hint here is that the variable "y" represent a point on the line that connects the end points (0,b) and (a,0).

The first step to solve this problem is to get the expression of this line.

The slope of this line is:   m = (0 - b)/(a - 0) = -b/a

Because the point (x,y) is on this line we have:   y - b = m(x - 0)

                                                                      y = (-b/a)x + b

Solution: Area of the rectangle = x*y = x*((-b/a)x + b) = (-b/a)x2 +bx

6 0
3 years ago
Can someone please help me with this???
tino4ka555 [31]

Answer:

1 cm

Step-by-step explanation:

To solve this problem we can use the Pythagorean theorem. In fact the diagonal of a rectangle is an hypotenuse of a right triangle, while the length is a leg. The width is the other leg

width = √2^2 - (√3)^2 = √4 - 3 = √1 = 1 cm

8 0
2 years ago
5+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B16x%5E%7B2%7D%20-37x-2%20%7D%3D4x" id="TexFormula1" title="\sqrt{16x^{2} -37x-2 }=
bonufazy [111]

Answer:

Step-by-step explanation:

\sqrt{16x^2-37x-2} =4x-5\\squaring~ both~sides\\16x^2-37x-2=16x^2-40x+25 ~[(a-b)^2=a^2-2ab+b^2]\\16x^2-37x-2-16x^2+40x-25=0\\3x-27=0\\3(x-9)=0\\x-9=0\\x=9

4 0
3 years ago
Money of Rp. 24,000.00 can buy 3 kg of apples. If Anto buys apples with money
ss7ja [257]

Answer:

5 Kg of apples

Step-by-step explanation:

cost of apples per kg = 24000.00/3

=8000.00

amount of apples bought = 40000.00/8000.00

=5 Kg

He got 5kg of apples with Rp.40,000.00

8 0
2 years ago
How do you solve these problems?
Rzqust [24]
A)

\bf log_4(x)=3\\\\&#10;-----------------------------\\\\&#10;log_{{  a}}{{  a}}^x\implies x\qquad \qquad &#10;\boxed{{{  a}}^{log_{{  a}}x}=x}\impliedby &#10;\begin{array}{llll}&#10;\textit{we'll use this}\\&#10;\textit{cancellation rule}&#10;\end{array}\\\\&#10;-----------------------------\\\\&#10;4^{\cfrac{}{}log_4(x)}=4^3\implies x=4^3

b)

\bf 3^{2y}=81\qquad &#10;\begin{cases}&#10;81=3\cdot 3\cdot 3\cdot 3\\&#10;\qquad 3^4&#10;\end{cases}\implies 3^{2y}=3^4\impliedby &#10;\begin{array}{llll}&#10;\textit{same base}\\&#10;exponents\\&#10;must\ be\\&#10;the\ same&#10;\end{array}&#10;\\\\\\&#10;2y=4\implies y=\cfrac{4}{2}\implies y=2
6 0
3 years ago
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