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irinina [24]
3 years ago
10

What is the factored form of 8x²-36x-20?

Mathematics
2 answers:
jarptica [38.1K]3 years ago
8 0

Answer:

(8x+4) ( x-5)

Step-by-step explanation:

Well we can't factor out the 8 and solve because if we do the -20 and -36 will be decimals.

So we do this

8 * -20 = -160

We need to find 2 number that multiplies  to -160 and adds to -36

-40 and 4 fit this category

they add to -36 and multiply to -160

Now we write the equation as

8x^2 - 40x + 4x -20

(8x^2-40x) (4x-20)

8x(x-5) + 4(x-5)

(8x+4) ( x-5)

abruzzese [7]3 years ago
7 0

Answer:

(4x + 2)( 2x - 10)

Step-by-step explanation:

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Anon25 [30]

Answer: (-9,11)

So the line starts at the left on -9 and ends at the right at 11 so then your answer would be (-9,11)

6 0
3 years ago
What is the radius of a circle that has a circumference of 81 π square inches?
ira [324]

Answer:

r≈12.89

Step-by-step explanation:

Using the formula

C=2πr

Solving for r

r=C

2π=81

2·π≈12.89155

6 0
3 years ago
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The base of a juice glass is in the shape of a circle
antoniya [11.8K]
The answer is going to be c
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4 years ago
40 points plz help if u can Which function has no Zeroes? Select all that apply.
Damm [24]
<h3>2 Answers: Choice C and choice D</h3>

y = csc(x) and y = sec(x)

==========================================================

Explanation:

The term "zeroes" in this case is the same as "roots" and "x intercepts". Any root is of the form (k, 0), where k is some real number. A root always occurs when y = 0.

Use GeoGebra, Desmos, or any graphing tool you prefer. If you graphed y = cos(x), you'll see that the curve crosses the x axis infinitely many times. Therefore, it has infinitely many roots. We can cross choice A off the list.

The same applies to...

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So we can rule out choices B, E and F.

Only choice C and D have graphs that do not have any x intercepts at all.

------------

If you're curious why csc doesn't have any roots, consider the fact that

csc(x) = 1/sin(x)

and ask yourself "when is that fraction equal to zero?". The answer is "never" because the numerator is always 1, and the denominator cannot be zero. If the denominator were zero, then we'd have a division by zero error. So that's why csc(x) can't ever be zero. The same applies to sec(x) as well.

sec(x) = 1/cos(x)

7 0
3 years ago
I am confused help me
bonufazy [111]
2x+3=17
subtract 3 from both sides
2x=14
divide both sides by 2 and get
x=7
4 0
3 years ago
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