Answer:

Step-by-step explanation:
In order to solve this problem, one must use the trigonometric ratios. These ratios are the following,

Remember, each side is named relative to the angle, thus sides will attain different names depending on the angle which one sues to calculate with.
In this case, one is given the measure of the angle, and the measure of the side opposite to the angle. One is asked to find the measure of the side adjacent to the angle. Use the trigonometric ratio (
) to solve for the unknown. Substitute in the given values,

Manipulate the equation such that it is solved for the parameter(x),

Solve,

(6g) and (-h) are the 2 terms in the expression
Answer:
The equation of the straight line in Slope- intercept form
y = 3 x - 11
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given points are (2,-5) and (8, 13)
The Slope of the line

Equation of the line having slope 'm' and given point

(x₁ , y₁) = ( 2, -5 )

y + 5 = 3x - 6
The equation of the straight line in slope intercept form
y = m x + c
y = 3 x - 6-5
y = 3 x - 11
<u><em>Final answer:</em></u>-
The equation of the straight line in Slope- intercept form
y = 3 x - 11
<h3>
Answer:</h3>
x² -6x = -13 ⇒ x ∈ {3-2i, 2+2i}
<h3>
Step-by-step explanation:</h3>
To make a=1, divide the equation by the coefficient of x², which is 8.
... x² -6x = -13 . . . . . . your blanks are filled with -6 and -13
Now, to complete the square, add the square of half the x-coefficient:
... (-6/2)² = 9.
... x² -6x +9 = -4 . . . 9 added to both sides
... (x -3)² = -4 . . . . . rewrite as a square
... x -3 = ±2i . . . . . . take the square root
... x = 3 ±2i . . . . . . . add 3
The solutions are the complex numbers x = 3 ±2i.
Answer:3.14
Step-by-step explanation:
Volume of cylinder can be calculated by using the formula V= pir^2h
Where r is radius of cylinder and h is the height.
A cylinder with radius 1 inch and height of 1 inch is given.
r=1,h=1,π=3.14.
Substituting the given values :
V=3.14(1)^2(1)
Volume of cylinder rounded to nearest tenth is 3.14 cubic inches .
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