Solve the system using elimination
2 answers:
Answer:
(3, 2)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define systems</u>
2x + 5y = 16
3x - 5y = -1
<u>Step 2: Solve for </u><em><u>x</u></em>
- Eliminate <em>y</em> (add equations): 5x = 15
- Divide 5 on both sides: x = 3
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define equation: 2x + 5y = 16
- Substitute in <em>x</em>: 2(3) + 5y = 16
- Multiply: 6 + 5y = 16
- Subtract 6 on both sides: 5y = 10
- Divide 5 on both sides: y = 2
Answer:
<em>(3, 2) </em>
Step-by-step explanation:
2x + 5y = 16 ........ <em>(1)</em>
3x - 5y = - 1 ......... <em>(2)</em>
<em>(1) </em>+<em> (2)</em>
( 2x + 3x ) + [ 5y + ( - 5y)] = 16 + (- 1)
5x = 15 ⇒ x = 3
2(3) + 5y = 16 ⇒ y = 2
<em>(3, 2)</em>
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